View an Example Question Help Translate the staternentinto a conlidence interval. ApproximIate the level of conlidece In a survey of 855 adults in a country 81 said being able to speak the language is at the core ct national identily. The survey's margin of error is 4.2% The level of conidence, C, for the interval (0.768,0.852) is ecual to the area under the standard normal curve between - Z, and z. Either technolcgy or a standard normal distribution table can be used to find the area. For the purposes of this solution, use technclcgy to determine the area to the let of- z = -3.13 and the area to the left of z, 3.13. rouding to four decimal places Area to the left of z Area to the left of - z = 0.0009 0.9991 Find the approximate value of the level of confidence c by solving for the pcsitive difference between the two areas Press Continue to see more.

MATLAB: An Introduction with Applications
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Author:Amos Gilat
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How can you find the left area of  zc= -3.13and -zc values using a ti-83 calculator

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Translate the staternentinto a conlidence interval. ApproximIate the level of conlidece
In a survey of 855 adults in a country 81 said being able to speak the language is at the core ct national
identily. The survey's margin of error is 4.2%
The level of conidence, C, for the interval (0.768,0.852) is ecual to the area under the standard normal curve
between - Z, and z. Either technolcgy or a standard normal distribution table can be used to find the area.
For the purposes of this solution, use technclcgy to determine the area to the let of- z = -3.13 and the area
to the left of z, 3.13. rouding to four decimal places
Area to the left of z
Area to the left of - z
= 0.0009
0.9991
Find the approximate value of the level of confidence c by solving for the pcsitive difference between the two
areas
Press Continue to see more.
Transcribed Image Text:View an Example Question Help Translate the staternentinto a conlidence interval. ApproximIate the level of conlidece In a survey of 855 adults in a country 81 said being able to speak the language is at the core ct national identily. The survey's margin of error is 4.2% The level of conidence, C, for the interval (0.768,0.852) is ecual to the area under the standard normal curve between - Z, and z. Either technolcgy or a standard normal distribution table can be used to find the area. For the purposes of this solution, use technclcgy to determine the area to the let of- z = -3.13 and the area to the left of z, 3.13. rouding to four decimal places Area to the left of z Area to the left of - z = 0.0009 0.9991 Find the approximate value of the level of confidence c by solving for the pcsitive difference between the two areas Press Continue to see more.
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