Vial No. A (ml) B (ml) C (ml) H20 1 2 5 Tris/HCl buffer pH7|1 1 1 Tumour cells (5% (w/v)) in buffer 1 3 4 Glucose [25mM] 0.5 0.75 1 Table 1. Based on Table 1, calculate the glucose concentration /1 gram tumour cells in conditions A, B and C. Show your workings. (a) Weight of tumour cells Sample A: 0.0142857 g/ml = 0.014 g/ml Sample B: 0.02222222 g/ml = 0.022 g/ml Sample C:0.01818182 g/ml = 0.018 g/ml (b) Glucose concentration Sample A : 3.571426 mM / 1000 = 0.003571426 M = 0.0036 M/ml Sample B: 2.77777778 mM / 1000 = 0.00277778 M = 0.0028 M/ml Sample C: 2.27272727 mM / 1000 = 0.00227273 M = 0.0023 M/ml
Vial No. A (ml) B (ml) C (ml) H20 1 2 5 Tris/HCl buffer pH7|1 1 1 Tumour cells (5% (w/v)) in buffer 1 3 4 Glucose [25mM] 0.5 0.75 1 Table 1. Based on Table 1, calculate the glucose concentration /1 gram tumour cells in conditions A, B and C. Show your workings. (a) Weight of tumour cells Sample A: 0.0142857 g/ml = 0.014 g/ml Sample B: 0.02222222 g/ml = 0.022 g/ml Sample C:0.01818182 g/ml = 0.018 g/ml (b) Glucose concentration Sample A : 3.571426 mM / 1000 = 0.003571426 M = 0.0036 M/ml Sample B: 2.77777778 mM / 1000 = 0.00277778 M = 0.0028 M/ml Sample C: 2.27272727 mM / 1000 = 0.00227273 M = 0.0023 M/ml
Biochemistry
9th Edition
ISBN:9781319114671
Author:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.
Publisher:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.
Chapter1: Biochemistry: An Evolving Science
Section: Chapter Questions
Problem 1P
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please help
![Vial No.
A (ml)
В (ml)
C (ml)
H20
1
2
5
Tris/HCI buffer pH7
1
1
1
Tumour cells (5%
(w/v)) in buffer
1
3
4
Glucose [25mM]
0.5
0.75
1
Table 1.
Based on Table 1, calculate the glucose concentration / 1 gram tumour cells in conditions A,
B and C. Show your workings.
(a)
Weight of tumour cells
Sample A: 0.0142857 g/ml = 0.014 g/ml
Sample B: 0.02222222 g/ml = 0.022 g/ml
Sample C:0.01818182 g/ml = 0.018 g/ml
(b)
Glucose concentration
Sample A : 3.571426 mM / 1000 = 0.003571426 M = 0.0036 M/ml
Sample B: 2.77777778 mM / 1000 = 0.00277778 M = 0.0028 M/ml
Sample C: 2.27272727 mM / 1000 = 0.00227273 M = 0.0023 M/ml](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fe4b2eb66-6876-46cd-8986-470643caa28d%2F4f9ca1b1-bc4f-45e5-8f11-5e9281041edf%2Fse41vpr_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Vial No.
A (ml)
В (ml)
C (ml)
H20
1
2
5
Tris/HCI buffer pH7
1
1
1
Tumour cells (5%
(w/v)) in buffer
1
3
4
Glucose [25mM]
0.5
0.75
1
Table 1.
Based on Table 1, calculate the glucose concentration / 1 gram tumour cells in conditions A,
B and C. Show your workings.
(a)
Weight of tumour cells
Sample A: 0.0142857 g/ml = 0.014 g/ml
Sample B: 0.02222222 g/ml = 0.022 g/ml
Sample C:0.01818182 g/ml = 0.018 g/ml
(b)
Glucose concentration
Sample A : 3.571426 mM / 1000 = 0.003571426 M = 0.0036 M/ml
Sample B: 2.77777778 mM / 1000 = 0.00277778 M = 0.0028 M/ml
Sample C: 2.27272727 mM / 1000 = 0.00227273 M = 0.0023 M/ml
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