vertice (0,e) and (6,2) asymptotes y = ax and y=4-22 The Standard form of Hyperbola is; with horrential tranverge asy. (x-4) ²- (y-x)² = 6² in the given vertices verticy of the the I Coordinate of both the hyperbola are same, it meary that Hyperbola hay horizontal tramvyverse axis. verticey are (hta, k) Cluation of asymptotes, F y=k+b(x-h) and y=k-b(x-h) "the mild point of the a : Center is "vertice); Center (hak) = (0+62+2) (²) Solution (h, k) = (3,2) The distance between the verticy is qual to 29, 2a= 6-0 a=3 Comparing the equations of asymptoty and Ⓒ, b=2 valuy of (h.K) (2-3)² 3² 3 and → b put in quation 1, (y-2)² = 1

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter11: Topics From Analytic Geometry
Section11.3: Hyperbolas
Problem 36E
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Question
Explain it to me. How do you came up with 2
vertice (0,2) and (6,2)
asymptotes y = 2²
The Standard form of Hyperbola is; with horizential.
tranverge aus.
in the
vertices of the
the
(x-7) ²_ (y-x)² =1
-
9²
6²
given verticy
I Coordinaty of both the
hyperbola are Jame, it meary.
that
and y= 4-2
Solution
Hyperbola hay horizontal tranyverse axis.
vertice are (hta, k)
Cluation of asymptotes,
.
g=k+ b (x-h) and y=k-b(x-h)
"the midpoint of the vertices;
: Center is
Center (tok) = (0+ 6, 2+2).
2a= 6-0
2a=6
a=3
(h.k)= (3,2)
The distance between the verticy is qual to 29,
(2-3) ²
32
3
Comparing the equations of asymplatey and Ⓡ,
+ 6 = +3
2
b=2
valuy of (h.K)
3
a
and
2
b put in quation 1,
(y-2)² = 1
2
2
Transcribed Image Text:vertice (0,2) and (6,2) asymptotes y = 2² The Standard form of Hyperbola is; with horizential. tranverge aus. in the vertices of the the (x-7) ²_ (y-x)² =1 - 9² 6² given verticy I Coordinaty of both the hyperbola are Jame, it meary. that and y= 4-2 Solution Hyperbola hay horizontal tranyverse axis. vertice are (hta, k) Cluation of asymptotes, . g=k+ b (x-h) and y=k-b(x-h) "the midpoint of the vertices; : Center is Center (tok) = (0+ 6, 2+2). 2a= 6-0 2a=6 a=3 (h.k)= (3,2) The distance between the verticy is qual to 29, (2-3) ² 32 3 Comparing the equations of asymplatey and Ⓡ, + 6 = +3 2 b=2 valuy of (h.K) 3 a and 2 b put in quation 1, (y-2)² = 1 2 2
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