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Vertical Horizontal Ax = Vort Vz = Vox 1 Ay = voyt -gt? Vy = Voy - gt Max Height

Vertical Horizontal Ax = Vort Vz = Vox 1 Ay = voyt -gt? Vy = Voy - gt Max Height

Database System Concepts
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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Create java , construction object and  classes ,Decisions,loop.

 

Horizontal Ax = Voxt Vz = Vox Vertical 1 Ay = voyt – 5gt? %3D Vy = Voy - gt Max Height Vo Sample run 2: Enter angle Theta between 0 and 90 degrees: 55.6 Enter positive velocity value : 21.4 Result : -+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+- Time (s) x (m) vx (m/s) у (m) vy (m/s) -+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+- 0.000 0.00 12.09 0.00 17.66 0.500 6.05 12.09 7.60 12.75 1.000 12.09 12.09 12.75 7.85 1.500 18.14 12.09 15.45 2.94 2.000 24.18 12.09 15.69 -1.96 2.500 30.23 12.09 13.49 -6.87 3.000 36.27 12.09 8.83 -11.77 3.500 42.32 12.09 1.71 -16.68 -+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+- Max height: 15.89 (m) at time: 1.800 (s) BUILD SUCCESSFUL (total time: 8 seconds) Sample run 3: Enter angle Theta between 0 and 90 degrees: -52 Enter angle Theta between 0 and 90 degrees: -10 Enter angle Theta between 0 and 90 degrees: 90 Enter positive velocity value : -40 Enter positive velocity value : 20 Result : -+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+- vx (m/s) -+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+- Time (s) x (m) у (m) vy (m/s) 0.000 0.00 0.00 0.00 20.00 0.00 0.00 0.500 0.00 8.77 15.09 1.000 0.00 15.10 10.19 1.500 0.00 0.00 18.96 5.28 2.000 0.00 0.00 20.38 0.38 2.500 0.00 0.00 19.34 -4.52 3.000 0.00 0.00 15.86 -9.43 3.500 0.00 0.00 9.91 -14.33 4.000 0.00 0.00 1.52 -19.24 -+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+- Max height: 20.39 (m) at time: 2.040 (s) BUILD SUCCESSFUL (total time: 27 seconds)
Transcribed Image Text:Horizontal Ax = Voxt Vz = Vox Vertical 1 Ay = voyt – 5gt? %3D Vy = Voy - gt Max Height Vo Sample run 2: Enter angle Theta between 0 and 90 degrees: 55.6 Enter positive velocity value : 21.4 Result : -+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+- Time (s) x (m) vx (m/s) у (m) vy (m/s) -+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+- 0.000 0.00 12.09 0.00 17.66 0.500 6.05 12.09 7.60 12.75 1.000 12.09 12.09 12.75 7.85 1.500 18.14 12.09 15.45 2.94 2.000 24.18 12.09 15.69 -1.96 2.500 30.23 12.09 13.49 -6.87 3.000 36.27 12.09 8.83 -11.77 3.500 42.32 12.09 1.71 -16.68 -+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+- Max height: 15.89 (m) at time: 1.800 (s) BUILD SUCCESSFUL (total time: 8 seconds) Sample run 3: Enter angle Theta between 0 and 90 degrees: -52 Enter angle Theta between 0 and 90 degrees: -10 Enter angle Theta between 0 and 90 degrees: 90 Enter positive velocity value : -40 Enter positive velocity value : 20 Result : -+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+- vx (m/s) -+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+- Time (s) x (m) у (m) vy (m/s) 0.000 0.00 0.00 0.00 20.00 0.00 0.00 0.500 0.00 8.77 15.09 1.000 0.00 15.10 10.19 1.500 0.00 0.00 18.96 5.28 2.000 0.00 0.00 20.38 0.38 2.500 0.00 0.00 19.34 -4.52 3.000 0.00 0.00 15.86 -9.43 3.500 0.00 0.00 9.91 -14.33 4.000 0.00 0.00 1.52 -19.24 -+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+- Max height: 20.39 (m) at time: 2.040 (s) BUILD SUCCESSFUL (total time: 27 seconds)
Problem: Consider a ball is kicked at an angle 0 (in degrees) from the horizontal with an initial velocity vo m/s. Write a java program that ask the user for values of 0 and vo m/s (meter per second) and accordingly it simulates the ball movements in very short time intervals At millisecond (ms). You will take the time interval for measurements at a standard interval of At = 10 ms and determine the football position Ax and Ay (i.e. x and y coordinate). For the next iteration the new Ax and Ay will be used to update the distance. Run the simulation until the football falls back to earth. Your program computes and displays the position (x and y coordinates) and the velocity (v and v,) of the football to record its dynamic-motion until it hits the ground. Calculate x and y every 10 ms but print the values every 500 ms with the format as shown in sample runs figures below. Create a NetBeans project named HW1_Yourld. Submit “HW1_Yourld.java" source file to the Moodle. Sample run 1: Enter angle Theta between 0 and 90 degrees: 37 Enter positive velocity value : 40 Result : -+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+- Time (s) х (m) vx (m/s) у (m) vy (m/s) -+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+- 0.000 0.00 31.95 0.00 24.07 0.500 15.97 31.95 10.81 19.17 1.000 31.95 31.95 19.17 14.26 1.500 47.92 31.95 25.07 9.36 2.000 63.89 31.95 28.53 4.45 2.500 79.86 31.95 29.53 -0.45 3.000 95.84 31.95 28.07 -5.36 3.500 111.81 31.95 24.17 -10.26 4.000 127.78 31.95 17.81 -15.17 4.500 143.75 31.95 9.00 -20.07 -+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+- Max height: 29.54 (m) at time: 2.450 (s) BUILD SUCCESSFUL (total time: 3 seconds) components in the x and y directions. The initial velocity and horizontal displacement in the x-direction is given by vox = vo cos0 and Ax = vox.At. Whereas velocity in the y- direction and the vertical displacement is given by voy = vo sin0 and Ay = Voy.At – 0.5g(At)². Where gravity g = 9.81 m/s² is the gravity force of the Earth. For the next iteration the new Ax and Ay will be used to update the distance.
Transcribed Image Text:Problem: Consider a ball is kicked at an angle 0 (in degrees) from the horizontal with an initial velocity vo m/s. Write a java program that ask the user for values of 0 and vo m/s (meter per second) and accordingly it simulates the ball movements in very short time intervals At millisecond (ms). You will take the time interval for measurements at a standard interval of At = 10 ms and determine the football position Ax and Ay (i.e. x and y coordinate). For the next iteration the new Ax and Ay will be used to update the distance. Run the simulation until the football falls back to earth. Your program computes and displays the position (x and y coordinates) and the velocity (v and v,) of the football to record its dynamic-motion until it hits the ground. Calculate x and y every 10 ms but print the values every 500 ms with the format as shown in sample runs figures below. Create a NetBeans project named HW1_Yourld. Submit “HW1_Yourld.java" source file to the Moodle. Sample run 1: Enter angle Theta between 0 and 90 degrees: 37 Enter positive velocity value : 40 Result : -+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+- Time (s) х (m) vx (m/s) у (m) vy (m/s) -+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+- 0.000 0.00 31.95 0.00 24.07 0.500 15.97 31.95 10.81 19.17 1.000 31.95 31.95 19.17 14.26 1.500 47.92 31.95 25.07 9.36 2.000 63.89 31.95 28.53 4.45 2.500 79.86 31.95 29.53 -0.45 3.000 95.84 31.95 28.07 -5.36 3.500 111.81 31.95 24.17 -10.26 4.000 127.78 31.95 17.81 -15.17 4.500 143.75 31.95 9.00 -20.07 -+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+- Max height: 29.54 (m) at time: 2.450 (s) BUILD SUCCESSFUL (total time: 3 seconds) components in the x and y directions. The initial velocity and horizontal displacement in the x-direction is given by vox = vo cos0 and Ax = vox.At. Whereas velocity in the y- direction and the vertical displacement is given by voy = vo sin0 and Ay = Voy.At – 0.5g(At)². Where gravity g = 9.81 m/s² is the gravity force of the Earth. For the next iteration the new Ax and Ay will be used to update the distance.
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