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versible non flow constant pressure process from initial volume =1.2 cubic eter and initial pressure = 690 kPa to a state where final temperature = 600 %3D

versible non flow constant pressure process from initial volume =1.2 cubic eter and initial pressure = 690 kPa to a state where final temperature = 600 %3D

Elements Of Electromagnetics
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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An oxygen gas R = 0.2598 KJ/kg°k and k = 1.395. If 4 kg of oxygen undergo a reversible non flow constant pressure process from initial volume =1.2 cubic meter and initial pressure = 690 kPa to a state where final temperature = 600°C. From the above statement: What is the initial temperature ? * 786.76°K 797.10 °K 876.50°K 796.77 °K Other: Determine the constant volume specific heat. * 0.6580 KJ/Kg-°K 0.6568 KJ/Kg-°K 0.5897 KJ/Kg- K 0.6577 KJ/Kg-°K
Transcribed Image Text:An oxygen gas R = 0.2598 KJ/kg°k and k = 1.395. If 4 kg of oxygen undergo a reversible non flow constant pressure process from initial volume =1.2 cubic meter and initial pressure = 690 kPa to a state where final temperature = 600°C. From the above statement: What is the initial temperature ? * 786.76°K 797.10 °K 876.50°K 796.77 °K Other: Determine the constant volume specific heat. * 0.6580 KJ/Kg-°K 0.6568 KJ/Kg-°K 0.5897 KJ/Kg- K 0.6577 KJ/Kg-°K
Determine the Change in Internal Energy. * 200.55 KJ 200.60 KJ 199.54 KJ 198.45 KJ Determine the constant pressure specific heat.* 0.8580 KJ/Kg-'K 0.7843 KJ/kg-°K O 0.9865 KJ/kg-°K 0.9175 KJ/kg-°K Determine the Change in Enthalpy. * O 279.76 KJ O 278.49 KJ 279.60 KJ 278.59 KJ
Transcribed Image Text:Determine the Change in Internal Energy. * 200.55 KJ 200.60 KJ 199.54 KJ 198.45 KJ Determine the constant pressure specific heat.* 0.8580 KJ/Kg-'K 0.7843 KJ/kg-°K O 0.9865 KJ/kg-°K 0.9175 KJ/kg-°K Determine the Change in Enthalpy. * O 279.76 KJ O 278.49 KJ 279.60 KJ 278.59 KJ
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