Verifying Inverse Functions In Exercises 21–32, verify that f and g are inverse functions (a) algebraically and (b) graphically. 21. f(x) = x − 5, g(x) = x + 5 22. f(x) = 2x, g(x) = x 2 23. f(x) = 7x + 1, g(x) = x − 1 7 24. f(x) = 3 − 4x, g(x) = 3 − x 4 25. f(x) = x3, g(x) = √ 3 x 26. f(x) = x3 3 , g(x) = √ 3 3x 27. f(x) = √x + 5, g(x) = x2 − 5, x ≥ 0 28. f(x) = 1 − x3, g(x) = √ 3 1 − x 29. f(x) = 1 x , g(x) = 1 x 30. f(x) = 1 1 + x , x ≥ 0, g(x) = 1 − x x , 0 < x ≤ 1 31. f(x) = x − 1 x + 5 , g(x) = −5x + 1 x − 1 32. f(x) = x + 3 x − 2 , g(x) = 2x + 3 x − 1
Verifying Inverse Functions In Exercises 21–32, verify that f and g are inverse functions (a) algebraically and (b) graphically. 21. f(x) = x − 5, g(x) = x + 5 22. f(x) = 2x, g(x) = x 2 23. f(x) = 7x + 1, g(x) = x − 1 7 24. f(x) = 3 − 4x, g(x) = 3 − x 4 25. f(x) = x3, g(x) = √ 3 x 26. f(x) = x3 3 , g(x) = √ 3 3x 27. f(x) = √x + 5, g(x) = x2 − 5, x ≥ 0 28. f(x) = 1 − x3, g(x) = √ 3 1 − x 29. f(x) = 1 x , g(x) = 1 x 30. f(x) = 1 1 + x , x ≥ 0, g(x) = 1 − x x , 0 < x ≤ 1 31. f(x) = x − 1 x + 5 , g(x) = −5x + 1 x − 1 32. f(x) = x + 3 x − 2 , g(x) = 2x + 3 x − 1
Trigonometry (11th Edition)
11th Edition
ISBN:9780134217437
Author:Margaret L. Lial, John Hornsby, David I. Schneider, Callie Daniels
Publisher:Margaret L. Lial, John Hornsby, David I. Schneider, Callie Daniels
Chapter1: Trigonometric Functions
Section: Chapter Questions
Problem 1RE:
1. Give the measures of the complement and the supplement of an angle measuring 35°.
Related questions
Question
Verifying Inverse
Exercises 21–32, verify that f and g are
inverse functions (a) algebraically and
(b) graphically.
21. f(x) = x − 5, g(x) = x + 5
22. f(x) = 2x, g(x) = x
2
23. f(x) = 7x + 1, g(x) = x − 1
7
24. f(x) = 3 − 4x, g(x) = 3 − x
4
25. f(x) = x3, g(x) = √
3 x
26. f(x) = x3
3 , g(x) = √
3 3x
27. f(x) = √x + 5, g(x) = x2 − 5, x ≥ 0
28. f(x) = 1 − x3, g(x) = √
3 1 − x
29. f(x) = 1
x
, g(x) = 1
x
30. f(x) = 1
1 + x
, x ≥ 0, g(x) = 1 − x
x , 0 < x ≤ 1
31. f(x) = x − 1
x + 5
, g(x) = −5x + 1
x − 1
32. f(x) = x + 3
x − 2
, g(x) = 2x + 3
x − 1
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