Verify that the pair x(t) = e 20t, y(t) = e 4t is a solution to the given system below. Sketch the trajectory of the given solution in the phase plane. 5 dy dt = 4y dx d=20y dt Verify that the pair x(t), y(t) is a solution of the system. Select the correct choice below and fill in any answer boxes to complete your choice. (Type expressions using t as the variable.) OA. The pair x(t) = e 20t, y(t) = e 4t is a solution because in terms of t, x' (t) = OB. The pair x(t) = e 20t, y(t) = e 4t is a solution because in terms of t, and y'(t) = In terms of x and y, x'(t) = Sx(t) dt = and Sy(t) dt = | In terms of x and y, and y' (t) = Sx(t) d dt= and d y(t) dt =
Verify that the pair x(t) = e 20t, y(t) = e 4t is a solution to the given system below. Sketch the trajectory of the given solution in the phase plane. 5 dy dt = 4y dx d=20y dt Verify that the pair x(t), y(t) is a solution of the system. Select the correct choice below and fill in any answer boxes to complete your choice. (Type expressions using t as the variable.) OA. The pair x(t) = e 20t, y(t) = e 4t is a solution because in terms of t, x' (t) = OB. The pair x(t) = e 20t, y(t) = e 4t is a solution because in terms of t, and y'(t) = In terms of x and y, x'(t) = Sx(t) dt = and Sy(t) dt = | In terms of x and y, and y' (t) = Sx(t) d dt= and d y(t) dt =
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Verify that the pair x(t) = e 20t, y(t) = e 4t is a solution to the given system below. Sketch the trajectory of the given solution in the phase plane.
dx
d=20y = 4y
5 dy
dt
dt
Verify that the pair x(t), y(t) is a solution of the system. Select the correct choice below and fill in any answer boxes to complete your choice.
(Type expressions using t as the variable.)
OA. The pair x(t) = e 20t, y(t) = e 4t is a solution because in terms of t, x'(t) =
OB.
The pair x(t) = e 20t
C.
Ask my instructor
and y'(t) = In terms of x and y, x'(t) =
y(t) = et is a solution because in terms of t Sx(t) dt = and Sy(t) dt =
4t
In terms of x and y,
and y' (t) =
Sx(t) dt:
d
y(t) dt =
and
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