Verify that the indicated function y = p(x) is an explicit solution of the given first-order differential equation. y' = 2xy²; y = 1/(16-x²) When y = 1/(16 - x²), y' = Thus, in terms of x, 2xy2 = Since the left and right hand sides of the differential equation are equal when 1/(16-x2) is substituted for y, y = 1/(16-x2) is a solution. Proceed as in Example 6, by considering simply as a function and give its domain. (Enter your answer using interval notation.) Then by considering as a solution of the differential equation, give at least one interval I of definition. 0 (-00, 0) O [4,00) O (-4,4) (0,00) O (-00, -4]