Verify that the identity Lo 8 (1+²) = Log(1 + 2) — Log(1 − 2) holds when [z] < 1. Then, using the Maclaurin expansions of Log(1+z) and Log(1-2), find the Maclaurin expansion of Log[(1+z)/(1-z)].

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Verify that the identity
Log(2)
(1+²) = Log(1 + 2) — Log(1 − 2)
holds when |z| < 1. Then, using the Maclaurin expansions of Log(1+z) and
Log(1-z), find the Maclaurin expansion of Log[(1+z)/(1-z)].
Transcribed Image Text:Verify that the identity Log(2) (1+²) = Log(1 + 2) — Log(1 − 2) holds when |z| < 1. Then, using the Maclaurin expansions of Log(1+z) and Log(1-z), find the Maclaurin expansion of Log[(1+z)/(1-z)].
Expert Solution
Step 1: Given Information:

To prove that the identity:

               l o g open parentheses fraction numerator 1 plus z over denominator 1 minus z end fraction close parentheses equals l o g left parenthesis 1 plus z right parenthesis minus log left parenthesis 1 minus z right parenthesis space

hold when vertical line z vertical line less than 1.

To find the maclarurin expansion of log open square brackets bevelled fraction numerator left parenthesis 1 plus z right parenthesis over denominator left parenthesis 1 minus z right parenthesis end fraction close square brackets.

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