Verify that 1, is an eigenvalue of A and that x, is a corresponding eigenvector. 2, = 5, x, = (1, 2, –1) 3, х, 3D (-2, 1 0) -3, х3 3 (3, 0, 1) -2 2 -3 A = -6 = - -1 -2 -2 2 -3 1 1 Ax 2 1 -6 = 5 = 1,x1 -1 -2 -1 -1 -2 2 -3 -2 2 Ax2 = 1= 1,x2 2 1 -6 = -3 -1 -2 -2 2 -3 3 Ax3 = 1 -6 = 13x3 2 -3 -1 -2
Verify that 1, is an eigenvalue of A and that x, is a corresponding eigenvector. 2, = 5, x, = (1, 2, –1) 3, х, 3D (-2, 1 0) -3, х3 3 (3, 0, 1) -2 2 -3 A = -6 = - -1 -2 -2 2 -3 1 1 Ax 2 1 -6 = 5 = 1,x1 -1 -2 -1 -1 -2 2 -3 -2 2 Ax2 = 1= 1,x2 2 1 -6 = -3 -1 -2 -2 2 -3 3 Ax3 = 1 -6 = 13x3 2 -3 -1 -2
Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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Question
![Verify that 1, is an eigenvalue of A and that x, is a corresponding eigenvector.
2, = 5, x, = (1, 2, –1)
3, х, 3D (-2, 1 0)
-3, х3 3 (3, 0, 1)
-2
2 -3
A =
-6
= -
-1 -2
-2
2 -3
1
1
Ax
2
1 -6
= 5
= 1,x1
-1
-2
-1
-1
-2
2 -3
-2
2
Ax2 =
1= 1,x2
2
1 -6
= -3
-1
-2
-2
2 -3
3
Ax3 =
1 -6
= 13x3
2
-3
-1 -2](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Feca141aa-ff82-43a1-80a6-bde745a50f81%2F816da8ab-8098-4999-89cc-eba5f9f3c189%2Fl9byn4j_processed.png&w=3840&q=75)
Transcribed Image Text:Verify that 1, is an eigenvalue of A and that x, is a corresponding eigenvector.
2, = 5, x, = (1, 2, –1)
3, х, 3D (-2, 1 0)
-3, х3 3 (3, 0, 1)
-2
2 -3
A =
-6
= -
-1 -2
-2
2 -3
1
1
Ax
2
1 -6
= 5
= 1,x1
-1
-2
-1
-1
-2
2 -3
-2
2
Ax2 =
1= 1,x2
2
1 -6
= -3
-1
-2
-2
2 -3
3
Ax3 =
1 -6
= 13x3
2
-3
-1 -2
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