Verify that 1; is an eigenvalue of A and that x; is a corresponding eigenvector. 2 -3 1 = 5, x, = (1, 2, –1) 1 -6 , 12 = -3, x2 = (-2, 1 0) 23 = -3, x, = (3, 0, 1) -2 A = 2 -1 -2 %3D %3! |-2 4 3 -2 2 -3 1 2 6 2 = 1,x1 Ax1 2 1 -6 2 = 5 -1 -2 -1 -4 4 -2 2 -3 -2 -2 -4 1 = -3 1= 1,X2 Ax2 = 2 1 -6 1 -1 -2 2 -2 -6 -3 -2 2 -3 6 -6 Ax3: 1 -6 = -3 = 13x3 2 -1 -2 -3
Verify that 1; is an eigenvalue of A and that x; is a corresponding eigenvector. 2 -3 1 = 5, x, = (1, 2, –1) 1 -6 , 12 = -3, x2 = (-2, 1 0) 23 = -3, x, = (3, 0, 1) -2 A = 2 -1 -2 %3D %3! |-2 4 3 -2 2 -3 1 2 6 2 = 1,x1 Ax1 2 1 -6 2 = 5 -1 -2 -1 -4 4 -2 2 -3 -2 -2 -4 1 = -3 1= 1,X2 Ax2 = 2 1 -6 1 -1 -2 2 -2 -6 -3 -2 2 -3 6 -6 Ax3: 1 -6 = -3 = 13x3 2 -1 -2 -3
Algebra and Trigonometry (6th Edition)
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ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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![Verify that 1; is an eigenvalue of A and that x; is a corresponding eigenvector.
-2
2 -31 2, %3D5, х, 3D (1, 2, —1)
12 = -3, x, = (-2, 1 0)
13 = -3, x, = (3, 0, 1)
A =
2
1 -6
-1 -2
|-2
4
3
-2
2 -3
1
2
2
6
AX1
1 -6
= 5
= 1,X1
2
2
2
-1 -2
-1
-1
-4
4
2
-2
2 -3
2
2
-4
1
Ax, =
1 -6
= -3
1= 1,x2
2
1
%3D
-1 -2
2
-2
-6
-3
-2
2 -3
3
3
Ax3 =
6
-6
- -3 0
= 13x3
2
1 -6
-1 -2
-3](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F82216637-120a-49f2-90be-d2b1d1168646%2F8b82c07a-91ac-4790-851d-1d41a767695e%2Flac8ht7_processed.png&w=3840&q=75)
Transcribed Image Text:Verify that 1; is an eigenvalue of A and that x; is a corresponding eigenvector.
-2
2 -31 2, %3D5, х, 3D (1, 2, —1)
12 = -3, x, = (-2, 1 0)
13 = -3, x, = (3, 0, 1)
A =
2
1 -6
-1 -2
|-2
4
3
-2
2 -3
1
2
2
6
AX1
1 -6
= 5
= 1,X1
2
2
2
-1 -2
-1
-1
-4
4
2
-2
2 -3
2
2
-4
1
Ax, =
1 -6
= -3
1= 1,x2
2
1
%3D
-1 -2
2
-2
-6
-3
-2
2 -3
3
3
Ax3 =
6
-6
- -3 0
= 13x3
2
1 -6
-1 -2
-3
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