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Verify that 1; is an eigenvalue of A and that x; is a corresponding eigenvector. 2 -3 1 = 5, x, = (1, 2, –1) 1 -6 , 12 = -3, x2 = (-2, 1 0) 23 = -3, x, = (3, 0, 1) -2 A = 2 -1 -2 %3D %3! |-2 4 3 -2 2 -3 1 2 6 2 = 1,x1 Ax1 2 1 -6 2 = 5 -1 -2 -1 -4 4 -2 2 -3 -2 -2 -4 1 = -3 1= 1,X2 Ax2 = 2 1 -6 1 -1 -2 2 -2 -6 -3 -2 2 -3 6 -6 Ax3: 1 -6 = -3 = 13x3 2 -1 -2 -3

Verify that 1; is an eigenvalue of A and that x; is a corresponding eigenvector. 2 -3 1 = 5, x, = (1, 2, –1) 1 -6 , 12 = -3, x2 = (-2, 1 0) 23 = -3, x, = (3, 0, 1) -2 A = 2 -1 -2 %3D %3! |-2 4 3 -2 2 -3 1 2 6 2 = 1,x1 Ax1 2 1 -6 2 = 5 -1 -2 -1 -4 4 -2 2 -3 -2 -2 -4 1 = -3 1= 1,X2 Ax2 = 2 1 -6 1 -1 -2 2 -2 -6 -3 -2 2 -3 6 -6 Ax3: 1 -6 = -3 = 13x3 2 -1 -2 -3

Algebra and Trigonometry (6th Edition)
Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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Verify that 1; is an eigenvalue of A and that x; is a corresponding eigenvector. -2 2 -31 2, %3D5, х, 3D (1, 2, —1) 12 = -3, x, = (-2, 1 0) 13 = -3, x, = (3, 0, 1) A = 2 1 -6 -1 -2 |-2 4 3 -2 2 -3 1 2 2 6 AX1 1 -6 = 5 = 1,X1 2 2 2 -1 -2 -1 -1 -4 4 2 -2 2 -3 2 2 -4 1 Ax, = 1 -6 = -3 1= 1,x2 2 1 %3D -1 -2 2 -2 -6 -3 -2 2 -3 3 3 Ax3 = 6 -6 - -3 0 = 13x3 2 1 -6 -1 -2 -3
Transcribed Image Text:Verify that 1; is an eigenvalue of A and that x; is a corresponding eigenvector. -2 2 -31 2, %3D5, х, 3D (1, 2, —1) 12 = -3, x, = (-2, 1 0) 13 = -3, x, = (3, 0, 1) A = 2 1 -6 -1 -2 |-2 4 3 -2 2 -3 1 2 2 6 AX1 1 -6 = 5 = 1,X1 2 2 2 -1 -2 -1 -1 -4 4 2 -2 2 -3 2 2 -4 1 Ax, = 1 -6 = -3 1= 1,x2 2 1 %3D -1 -2 2 -2 -6 -3 -2 2 -3 3 3 Ax3 = 6 -6 - -3 0 = 13x3 2 1 -6 -1 -2 -3
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