Venus can be as bright as apparent magnitude -4.7 when at a distance of about 1AU. How many times fainter would Venus look from a distance of 7pc? Assume Venus has the same illumination phase from your new vantage point. (Hint: Recall the inverse square law; also, review the definition of apparent visual magnitudes. Note: 1 pc = 2.1 x 10^5 AU _______ times fainter what would it's apparently magnitude be?

Venus can be as bright as apparent magnitude -4.7 when at a distance of about 1AU. How many times fainter would Venus look from a distance of 7pc? Assume Venus has the same illumination phase from your new vantage point. (Hint: Recall the inverse square law; also, review the definition of apparent visual magnitudes. Note: 1 pc = 2.1 x 10^5 AU _______ times fainter what would it's apparently magnitude be?

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Imagine a giant ruler at the planet's distance that is 1 arcsecond across in your image. Given this angular length, and this distance to the ruler in AU, you can calculate the physical length of the ruler in AU. This will then allow you to convert your measurement of the semi-major axis from arcseconds to AU. 0/ 360° - length / circumference (of big circle) 360° 0 = angular length =1 arcsecond length
Venus can be as bright as apparent magnitude -4.7 when at a distance of about 1 AU. How many times fainter would Venus look from a distance of 5 pc? Assume Venus has the same illumination phase from your new vantage point. (Hints: Recall the inverse square law; also, review the definition of apparent visual magnitudes. ote: 1 pc = 2.1 x 10° AU). times fainter What would its apparent magnitude be? Need Help? Read It
UF, s In 2014, astronomers discovered 22 new KBOS, among those the following three: 2014 with a period of 331.1 years; 2014 TT, with a period of 280.8 years; 2014 QM with a period of 315.2 years. Given that information and knowing that Neptune's period is 85 441 164.8 years, which of those objects - if any- are likely part of the Plutino family of KBOS? Show your work that lead you to your conclusion.
F = 9/5 C + 32 ; C = 5/9 (F - 32); K = 273 + C; Lambda = 2900/T; T^4 = I (128)(10^8); I1/I2 = ( D2 / D1 )2 Show All Calculations What is the intensity of sunlight on planet XZEON if: The intensity of direct sunlight on earth is Ie = 2.0 calories per square centimeter per minute and Planet XZEON is 7.7 times farther from the sun than the earth is.
Venus can be as bright as apparent magnitude −4.7 when at a distance of about 1 AU. How many times fainter would Venus look from a distance of 7 pc? Assume Venus has the same illumination phase from your new vantage point. (Hints: Recall the inverse square law; also, review the definition of apparent visual magnitudes. Note: 1 pc = 2.1 ✕ 105 AU). [fill in the blank] times fainter What would its apparent magnitude be?
The planet Uranus was discovered in 1781, and Neptune, the next planet outward from the Sun, was discovered in 1846. Imagine you're an astronomer in 1846, and you start wondering if there's another planet out beyond Neptune. You decide to try and discover its existence using the same method that was used for Neptune. How will you do this? Group of answer choices You'll recruit a large number of astronomers to use their telescopes to carefully scan the sky in directions that are far from the ecliptic. The regions around the north and south celestial poles will probably be the best "hunting grounds" for the new planet. You'll examine Uranus and Neptune very carefully, on every clear night, for several years, to see if you can find any evidence that sunlight has been reflected off of the `new' planet, then off of Uranus or Neptune, before arriving on Earth. On rare occasions when Neptune passes in front of the Sun, as seen from Earth, you'll look carefully at the Sun (with a safe…
For the following light curve, which of the answers best illustrates the orientation of the exoplanet and its host star during the dip at Time 3? Light curve Time 1 Time 2 Time 3 Time 4 Choose one: А. O C. D. Intensity B.
A planet was recently discovered orbiting the star Proxima Centauri, with an orbital radius of 0.05 AU. As seen from Earth, what is the maximum angular separation between this planet and Proxima Centauri, in arcseconds? The distance to Proxima Centauri is 4.24 light-years.