#5 (3) At what horizontal velocity would you need to throw a ball off the roof of an 8.5 meter buildingif you wanted it to land 62.5 meters away from the base of the building? What would be thevertical velocity of the ball immediately before hitting the ground?(4) Referring back to question #3, at what velocity would you need to throw the ball if you wanted itto land twice as far away?(5) Referring again to question #3, suppose the building was twice the height. How far away wouldthe ball land if you threw it the same velocity as you answered in the first part of question #3?

Name: #5 (3) At what horizontal velocity would you need to throw a ball off
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Description: #5 (3) At what horizontal velocity would you need to throw a ball off the roof of an 8.5 meter buildingif you wanted it to land 62.5 meters away from the base of the building? What would be thevertical velocity of the ball immediately before hitting

Answered: Velocity would you need to throw a ball…

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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(3) At what horizontal velocity would you need to throw a ball off the roof of an 8.5 meter building
if you wanted it to land 62.5 meters away from the base of the building? What would be the
vertical velocity of the ball immediately before hitting the ground?
(4) Referring back to question #3, at what velocity would you need to throw the ball if you wanted it
to land twice as far away?
(5) Referring again to question #3, suppose the building was twice the height. How far away would
the ball land if you threw it the same velocity as you answered in the first part of question #3?

Expert Solution

Step 1

Given that:

The height of the roof is $y = 62.5 m$

The acceleration due to gravity is $g = 9.8 \frac{m}{s^{2}}$

The horizontal displacement is $x = 8.5 m$

It is required to find the vertical velocity of the ground.

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