velocity of the lower end by differentiating its position in terms of horizontal and vertical components. (Hint: Use the left fixed end of the bar as the origin of the frame. x direction is

Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
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EXERCISE 1.10 The collar slides to the left as the interconnected bars swing in
the vertical plane. The position of the collar is x = 20 sin (501) mm, and the
angles are 0₁ = 0.27 сos (50t), 0₂ = 0.27 sin (50t - n/3) rad. Determine the
velocity of the lower end by differentiating its position in terms of horizontal
and vertical components.
(Hint: Use the left fixed end of the bar as the origin of the frame. x direction is
along the bar to the right while y direction is perpendicular to the bar
downward.)
L₁
F₂
Transcribed Image Text:EXERCISE 1.10 The collar slides to the left as the interconnected bars swing in the vertical plane. The position of the collar is x = 20 sin (501) mm, and the angles are 0₁ = 0.27 сos (50t), 0₂ = 0.27 sin (50t - n/3) rad. Determine the velocity of the lower end by differentiating its position in terms of horizontal and vertical components. (Hint: Use the left fixed end of the bar as the origin of the frame. x direction is along the bar to the right while y direction is perpendicular to the bar downward.) L₁ F₂
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