Velocity (m/sec) 2 1 itime (sec) 14 !2 5!6 89 !12 -1 -2 -3 A.) B.) C.) D.) Determine the displacement between 2 and 3 s. Determine the velocity at 3 s. Determine the displacement between 8 and 9 s. What does the negative mean? Draw the position -vs- time graph for the first 6 s. Make the initial position x = 2 m.

College Physics
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ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
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Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
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Question
Velocity (m/sec)
3
1
time (sec)
14
!2
5 !6
8!9
12
-1
-2
-3
A.)
B.)
C.)
D.)
Determine the displacement between 2 and 3 s.
Determine the velocity at 3 s.
Determine the displacement between 8 and 9 s. What does the negative mean?
Draw the position -vs- time graph for the first 6 s. Make the initial position x = 2 m.
%3D
Transcribed Image Text:Velocity (m/sec) 3 1 time (sec) 14 !2 5 !6 8!9 12 -1 -2 -3 A.) B.) C.) D.) Determine the displacement between 2 and 3 s. Determine the velocity at 3 s. Determine the displacement between 8 and 9 s. What does the negative mean? Draw the position -vs- time graph for the first 6 s. Make the initial position x = 2 m. %3D
Expert Solution
Step 1

Displacement is defined as the Velocity multiplied with time. 

displacement = Velocity × time

A) From the given graph velocity reads as 2 m/s between the time 2 to 3 sec

so the displacement will be :

Displacement = (2 m/s)(3 s - 2 s)

                       = 2 m

B) From the graph the velocity of the object at time t = 3 sec is

v = 2 m/sec

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