Velocity 0 m/s Show Vector 12.0 6.0 0.0 -6.0 -12.0 0 (0,0) (3,6) (4,6) 3 (5.5, 0) 5 6 (7,-6) (8.5, -6) 9 Postion (10, 0) 10 sec Acceleration+ Image shows a Velocity (m/s) Vs Time (s) line graph. The points connecting on the graph are (0,0) (3,6) (4,6) (5.5,0) (7,-6) (8.5,-6) and (10,0).) Using the Moving Man PhET simulator, the above Velocity Vs Time graph was created over a ten second period. A student Sandy analyzed the graph and concluded that the moving man did not return to his original position and had a non-zero total displacement.
In the example, 2.5 m+5m+5m+5m+2.5 m= 20 m
-2.5+-5m+-5m+-2.5+-5m=-20 m
-20+20=0
So in the example it shows that the final positions are the same value. They subtract to zero, so the graph shows a total zero displacement over 8 seconds. DO NOT solve the example problem. Solve the mentioning Sandy.
Now look at the blank graph. Write or type the correct meters in EVERY box. All the boxes within the line should be filled in just like in the example. Then add all the positive meters up. Then add all the negative meters up. Then add the final meters on both sides together just like in example when 20 and -20 was added.
Does the graph show that the total displacement over 10 seconds is 0?
Hints:
1/2*3*6=9
1/2(1.5)(6)=4.5 m
6*1.5=9 m
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