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veights of the boxes and the applied horizontal force for each case are given in the indicated figures. The frictional force is 20% of the weight of the box (g= 10 N/kg). Rank the change in kinetic energy for each box from the greatest change in kinetic energy to the least change in kinetic energy. All boxes have an initial velocity of +10 m/s (+ direction is to the right and- to the left, with-4 <-2). 10 N 10 N 20 N = 100 N F = 50 N F = 100 N %3D A B C

veights of the boxes and the applied horizontal force for each case are given in the indicated figures. The frictional force is 20% of the weight of the box (g= 10 N/kg). Rank the change in kinetic energy for each box from the greatest change in kinetic energy to the least change in kinetic energy. All boxes have an initial velocity of +10 m/s (+ direction is to the right and- to the left, with-4 <-2). 10 N 10 N 20 N = 100 N F = 50 N F = 100 N %3D A B C

College Physics
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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The image shows four scenarios labeled D, E, F, G, and H, illustrating the interaction of blocks on a surface with horizontal forces applied to them. Each diagram depicts a block on a flat surface with a specific force \(F\) acting on it. The weight on each block varies as well: - **Diagram D:** A block with a weight of 20 N is acted upon by a force \(F = 50\) N. - **Diagram E:** A block with a weight of 10 N is acted upon by a force \(F = 10\) N. - **Diagram F:** A block with a weight of 20 N is acted upon by a force \(F = 10\) N. - **Diagram G:** A block with a weight of 50 N is acted upon by a force \(F = 10\) N. - **Diagram H:** A block with a weight of 100 N is acted upon by a force \(F = 20\) N. Below these diagrams, there is a ranking prompt: "Greatest 1 _____ 2 _____ 3 _____ 4 _____ 5 _____ 6 _____ 7 _____ 8 _____ Least" There is also an option to check if all changes in kinetic energy are the same. The task is to rank the scenarios from the greatest to least change in kinetic energy based on the given forces and weights. A space is provided for the explanation of the reasoning used to make this determination.
Transcribed Image Text:The image shows four scenarios labeled D, E, F, G, and H, illustrating the interaction of blocks on a surface with horizontal forces applied to them. Each diagram depicts a block on a flat surface with a specific force \(F\) acting on it. The weight on each block varies as well: - **Diagram D:** A block with a weight of 20 N is acted upon by a force \(F = 50\) N. - **Diagram E:** A block with a weight of 10 N is acted upon by a force \(F = 10\) N. - **Diagram F:** A block with a weight of 20 N is acted upon by a force \(F = 10\) N. - **Diagram G:** A block with a weight of 50 N is acted upon by a force \(F = 10\) N. - **Diagram H:** A block with a weight of 100 N is acted upon by a force \(F = 20\) N. Below these diagrams, there is a ranking prompt: "Greatest 1 _____ 2 _____ 3 _____ 4 _____ 5 _____ 6 _____ 7 _____ 8 _____ Least" There is also an option to check if all changes in kinetic energy are the same. The task is to rank the scenarios from the greatest to least change in kinetic energy based on the given forces and weights. A space is provided for the explanation of the reasoning used to make this determination.
**Problem Statement:** Various similar boxes are being pushed for 10 m across a floor by a horizontal force as shown below. The weights of the boxes and the applied horizontal force for each case are given in the indicated figures. The frictional force is 20% of the weight of the box \((g = 10 \, \text{N/kg})\). Rank the change in kinetic energy for each box from the greatest change in kinetic energy to the least change in kinetic energy. All boxes have an initial velocity of \(+10 \, \text{m/s} \) (+ direction is to the right and – to the left, with \(+4 < -2\)). **Diagrams:** - **Box A:** - Weight: 10 N - Applied Force: 100 N (right) - **Box B:** - Weight: 10 N - Applied Force: 50 N (right) - **Box C:** - Weight: 20 N - Applied Force: 100 N (right) - **Box D:** - Weight: 20 N - Applied Force: 50 N (right) - **Box E:** - Weight: 100 N - Applied Force: 10 N (right) - **Box F:** - Weight: 20 N - Applied Force: 10 N (right) **Analysis:** The frictional force for each box: - \( f = 0.2 \times \text{Weight} \) Calculate the net force for each box: - **Box A:** - Frictional force = \( 0.2 \times 10 \, \text{N} = 2 \, \text{N} \) - Net force = \( 100 \, \text{N} - 2 \, \text{N} = 98 \, \text{N} \) - **Box B:** - Frictional force = \( 0.2 \times 10 \, \text{N} = 2 \, \text{N} \) - Net force = \( 50 \, \text{N} - 2 \, \text{N} = 48 \, \text{N} \) - **Box C:** - Friction
Transcribed Image Text:**Problem Statement:** Various similar boxes are being pushed for 10 m across a floor by a horizontal force as shown below. The weights of the boxes and the applied horizontal force for each case are given in the indicated figures. The frictional force is 20% of the weight of the box \((g = 10 \, \text{N/kg})\). Rank the change in kinetic energy for each box from the greatest change in kinetic energy to the least change in kinetic energy. All boxes have an initial velocity of \(+10 \, \text{m/s} \) (+ direction is to the right and – to the left, with \(+4 < -2\)). **Diagrams:** - **Box A:** - Weight: 10 N - Applied Force: 100 N (right) - **Box B:** - Weight: 10 N - Applied Force: 50 N (right) - **Box C:** - Weight: 20 N - Applied Force: 100 N (right) - **Box D:** - Weight: 20 N - Applied Force: 50 N (right) - **Box E:** - Weight: 100 N - Applied Force: 10 N (right) - **Box F:** - Weight: 20 N - Applied Force: 10 N (right) **Analysis:** The frictional force for each box: - \( f = 0.2 \times \text{Weight} \) Calculate the net force for each box: - **Box A:** - Frictional force = \( 0.2 \times 10 \, \text{N} = 2 \, \text{N} \) - Net force = \( 100 \, \text{N} - 2 \, \text{N} = 98 \, \text{N} \) - **Box B:** - Frictional force = \( 0.2 \times 10 \, \text{N} = 2 \, \text{N} \) - Net force = \( 50 \, \text{N} - 2 \, \text{N} = 48 \, \text{N} \) - **Box C:** - Friction
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