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Vector Spaces Prove property 3 by rearranging the flig Property 3: For every element A, B, C_₂in V=M3x3, (ABB) CAD (BDC) A) Let aij, bij, cij, dij, ei; and the aith entries in A₁B₁C₁D = (ABB) # C, E = A (B+C), respectively 2 Suppose A, B, and C are in V = M₂x3 • from the definition of AB, dij -fai jx bij) x cij and eij aijx (bij x cij) So, (AB) C = A + (PDC) Since aij bij cij are are real #'s dijseij answer for ex FEDCBA M

Vector Spaces Prove property 3 by rearranging the flig Property 3: For every element A, B, C_₂in V=M3x3, (ABB) CAD (BDC) A) Let aij, bij, cij, dij, ei; and the aith entries in A₁B₁C₁D = (ABB) # C, E = A (B+C), respectively 2 Suppose A, B, and C are in V = M₂x3 • from the definition of AB, dij -fai jx bij) x cij and eij aijx (bij x cij) So, (AB) C = A + (PDC) Since aij bij cij are are real #'s dijseij answer for ex FEDCBA M

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Vector Spaces Prove property 3 by rearranging the flig Property 3: For every element A, B, C in V=M3x3, (AB) C= A + (BDC) A) Let aij, bij, cij, dij, ei; and the with entries in A₁B₁C₁D = (ABB) + C, E = A (BOC), respectively B) Suppose A, B, and C are in V = M3x3 в) c) from the definition of AB, dij -(aijx bij) x cij and eij = a i j x (bij x c i j ) 420932 D) SO, (AⓇB) ⓇC = A + (PDC) E Since aij, bij, cij are real #'s dij=eij ansue answer for ex FEDCBA AXA wh tast
Transcribed Image Text:Vector Spaces Prove property 3 by rearranging the flig Property 3: For every element A, B, C in V=M3x3, (AB) C= A + (BDC) A) Let aij, bij, cij, dij, ei; and the with entries in A₁B₁C₁D = (ABB) + C, E = A (BOC), respectively B) Suppose A, B, and C are in V = M3x3 в) c) from the definition of AB, dij -(aijx bij) x cij and eij = a i j x (bij x c i j ) 420932 D) SO, (AⓇB) ⓇC = A + (PDC) E Since aij, bij, cij are real #'s dij=eij ansue answer for ex FEDCBA AXA wh tast
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