Vector 4 is 24.4 units long, and is directed along the x-axis. Vector B is 24.3 units long, and is 123° counter-clockwise from the x-axis. Calculate the scalar product A.B. Your Answer:
Vector 4 is 24.4 units long, and is directed along the x-axis. Vector B is 24.3 units long, and is 123° counter-clockwise from the x-axis. Calculate the scalar product A.B. Your Answer:
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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![### Vector Scalar Product Calculation
#### Problem Statement
**Vector \( \vec{A} \)**:
- Length: 24.4 units
- Direction: Along the x-axis
**Vector \( \vec{B} \)**:
- Length: 24.3 units
- Direction: 123° counter-clockwise from the x-axis
#### Task
Calculate the scalar product (dot product) \( \vec{A} \cdot \vec{B} \).
#### Answer Input
- [Your Answer: _______]
### Explanation
To calculate the scalar product \( \vec{A} \cdot \vec{B} \), we use the formula:
\[ \vec{A} \cdot \vec{B} = |\vec{A}| |\vec{B}| \cos(\theta) \]
where:
- \( |\vec{A}| \) is the magnitude of vector \( \vec{A} \)
- \( |\vec{B}| \) is the magnitude of vector \( \vec{B} \)
- \( \theta \) is the angle between the vectors \( \vec{A} \) and \( \vec{B} \)
Given values:
- \( |\vec{A}| = 24.4 \)
- \( |\vec{B}| = 24.3 \)
- \( \theta = 123^\circ \)
Next, calculate the cosine of the angle:
\[ \cos(123^\circ) \]
Finally, plug the values into the formula to find the scalar product.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fd99dc5ee-0347-4b7c-8511-9a91331fbdb4%2Fae4b6dd0-b36a-4276-9815-583957d1e029%2Fvu9bwnb_processed.jpeg&w=3840&q=75)
Transcribed Image Text:### Vector Scalar Product Calculation
#### Problem Statement
**Vector \( \vec{A} \)**:
- Length: 24.4 units
- Direction: Along the x-axis
**Vector \( \vec{B} \)**:
- Length: 24.3 units
- Direction: 123° counter-clockwise from the x-axis
#### Task
Calculate the scalar product (dot product) \( \vec{A} \cdot \vec{B} \).
#### Answer Input
- [Your Answer: _______]
### Explanation
To calculate the scalar product \( \vec{A} \cdot \vec{B} \), we use the formula:
\[ \vec{A} \cdot \vec{B} = |\vec{A}| |\vec{B}| \cos(\theta) \]
where:
- \( |\vec{A}| \) is the magnitude of vector \( \vec{A} \)
- \( |\vec{B}| \) is the magnitude of vector \( \vec{B} \)
- \( \theta \) is the angle between the vectors \( \vec{A} \) and \( \vec{B} \)
Given values:
- \( |\vec{A}| = 24.4 \)
- \( |\vec{B}| = 24.3 \)
- \( \theta = 123^\circ \)
Next, calculate the cosine of the angle:
\[ \cos(123^\circ) \]
Finally, plug the values into the formula to find the scalar product.
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