Prove the suggested proofs by filling in the missing blanks.Given &HTA 4THA ,4TAR 2 4HAE,and Point A Is the midpoint of ERPROVE: ATAR AHAEReasons1. 4THA 4HTA)#602. AHAT is anisosceles triangle 2) #63. HA = TA#624. A is the midpointof ER4 #633 #645. EA = AR#655 #666. 4TAR 2 4HAE7. ATAR = AHAE

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ve the suggested proofs by filling in the missing blanks. Given &HTA s 4THA , 4TAR2 4HAE, and Point A Is the midpoint of ER Statements Reasons PROVE: ATARAHAE 1. 4THA = 4HTAD # 60 2. AHAT is an isosceles triangle # 61 2) 3) 3. HA = TA #62 4. A is the midpoint of ER 4 #63 #い4 5. EA = AR 6. 4TAR HAE #65 7. ATAR AHAE ) #66

ve the suggested proofs by filling in the missing blanks. Given &HTA s 4THA , 4TAR2 4HAE, and Point A Is the midpoint of ER Statements Reasons PROVE: ATARAHAE 1. 4THA = 4HTAD # 60 2. AHAT is an isosceles triangle # 61 2) 3) 3. HA = TA #62 4. A is the midpoint of ER 4 #63 #い4 5. EA = AR 6. 4TAR HAE #65 7. ATAR AHAE ) #66

Elementary Geometry For College Students, 7e

7th Edition

ISBN:9781337614085

Author:Alexander, Daniel C.; Koeberlein, Geralyn M.

Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.

ChapterP: Preliminary Concepts

SectionP.CT: Test

Problem 1CT

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Question

Prove the suggested proofs by filling in the missing blanks.
Given &HTA 4THA ,4TAR 2 4HAE,
and Point A Is the midpoint of ER
PROVE: ATAR AHAE
Reasons
1. 4THA 4HTA)
#60
2. AHAT is an
isosceles triangle 2) #6
3. HA = TA
#62
4. A is the midpoint
of ER
4 #63
3 #64
5. EA = AR
#65
5 #66
6. 4TAR 2 4HAE
7. ATAR = AHAE

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