Prove the suggested proofs by filling in the missing blanks.Given &HTA 4THA ,4TAR 2 4HAE,and Point A Is the midpoint of ERPROVE: ATAR AHAEReasons1. 4THA 4HTA)#602. AHAT is anisosceles triangle 2) #63. HA = TA#624. A is the midpointof ER4 #633 #645. EA = AR#655 #666. 4TAR 2 4HAE7. ATAR = AHAE

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ve the suggested proofs by filling in the missing blanks. Given &HTA s 4THA , 4TAR2 4HAE, and Point A Is the midpoint of ER Statements Reasons PROVE: ATARAHAE 1. 4THA = 4HTAD # 60 2. AHAT is an isosceles triangle # 61 2) 3) 3. HA = TA #62 4. A is the midpoint of ER 4 #63 #い4 5. EA = AR 6. 4TAR HAE #65 7. ATAR AHAE ) #66

ve the suggested proofs by filling in the missing blanks. Given &HTA s 4THA , 4TAR2 4HAE, and Point A Is the midpoint of ER Statements Reasons PROVE: ATARAHAE 1. 4THA = 4HTAD # 60 2. AHAT is an isosceles triangle # 61 2) 3) 3. HA = TA #62 4. A is the midpoint of ER 4 #63 #い4 5. EA = AR 6. 4TAR HAE #65 7. ATAR AHAE ) #66

Elementary Geometry For College Students, 7e

7th Edition

ISBN:9781337614085

Author:Alexander, Daniel C.; Koeberlein, Geralyn M.

Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.

Chapter4: Quadrilaterals

Section4.3: The Rectangle, Square, And Rhombus

Problem 45E: In square ABCD not shown, point E lies in the interior of ABCD in such a way that ABE is an...

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