ve the statement using the , & definition of a limit. 18 + 2x lim x → 1 5 = 4 en & > 0, we need 8 ---Select---✓ such that if 0 < |x-1| < 6, then 18+ 2x ose ---Select-- > |( ¹8 + ²x) - 4 | < 5 , then 0 < |x-1| < 6⇒ 18 + 2x 5 4 - 4 < E. Thus, lim x → 1 18+ 2x 5 = 4 by the definition of a limit. ---Select--- 18+ 2x 5 . But + |²x - ²1. - 1| < |x-1| <--Select--. So if we

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