A spring has a natural length of 15 ft. A force of 300 lb compresses the spring to 12 ft. Find the work done in compressing the spring from 13 cm to 10 ft.

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Q: spring has a natural length of 15 ft. A force of 300 lb compresses the spring to 12 ft. Find the…

A: natural length of spring = 15 ft force = 300 lb new length of spring = 12 ft

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A: Given that :Mass of elevator, m=700 kgAcceleration downward, a=3 m/s2Distance, d=12 m

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Q: A box is pulled with a force of 60 N to produce a displacement of 13 m. If the angle between the…

A: Given, Force F = 60 N Displacement d = 13 m Angle θ = 20 degree

Q: F2 = 20 N F1 = 40 N 30° ----- 30° F3 = 50 N

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Q: If a work of 0.4 joule is needed to stretch a spring a distance x=0.05m What is the force constant…

A: The work required to stretch a spring to a distance is given.

Q: It takes a force of 28.22 Newtons to stretch a 49-cm spring to 117-cm and hold it there. How much…

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Q: Calculate the work done by a 53 N force pushing a pencil 16cm

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Q: Calculate the work performed by a horse pulling a wagon forward with 150 N of force, across a bridge…

A: Force applied by the horse (F) = 150 N Length of bridge (L) = 50 m Mass of horse (M) = 50 kg

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Q: A 5.2kg box is raised from rest a distance 5.5m by an upward applied force of 3.4N. Find the work…

A: We will use work done formula,

Q: A force of 4 pounds is needed to stretch a spring 2 inches from its natural unstretched and…

A: Force, F = 4 pounds = 17.79 N Extension, x = 2 inches = 0.0508 m Change in length, ∆x = (15 - 10)…