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ve for the forces AB and AG. The forces are positive if in tension, negative if in c АВ

ve for the forces AB and AG. The forces are positive if in tension, negative if in c АВ

Elements Of Electromagnetics
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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I already found Ax=0,Ay=11.2 and Fy=11.2

how do I find the theta to solve for member AB?

also state if the members are is tension or compression.

The free-body diagram for joint A is shown. The diagram is drawn assuming that each member of the truss is in tension. Solve for the forces AB and AG. The forces are positive if in tension, negative if in compression. **Diagram Explanation:** - The diagram features the joint A with three forces acting on it. - Force \( AB \) is shown as a vector pointing upwards and to the right, representing tension along the member AB. - Force \( AG \) is depicted as a vector pointing directly to the right, indicating tension along the member AG. - Forces \( A_x \) and \( A_y \) are indicated as components of the reaction at the support, pointing left and down, respectively. **Answers:** - AB = [ ] kN - AG = [ ] kN
Transcribed Image Text:The free-body diagram for joint A is shown. The diagram is drawn assuming that each member of the truss is in tension. Solve for the forces AB and AG. The forces are positive if in tension, negative if in compression. **Diagram Explanation:** - The diagram features the joint A with three forces acting on it. - Force \( AB \) is shown as a vector pointing upwards and to the right, representing tension along the member AB. - Force \( AG \) is depicted as a vector pointing directly to the right, indicating tension along the member AG. - Forces \( A_x \) and \( A_y \) are indicated as components of the reaction at the support, pointing left and down, respectively. **Answers:** - AB = [ ] kN - AG = [ ] kN
**Text for Educational Website:** Because every joint has more than two unknowns, we will begin by solving for the external reactions. The free-body diagram of the entire structure is shown. Calculate \( A_x, A_y, \) and \( F_y \). **Diagram Explanation:** This is a structural free-body diagram with several forces and dimensions indicated: - The structure is composed of a series of interconnected members forming a shape similar to a truss. - There are vertical loads at points \( C \) and \( D \), each with a magnitude of 7.8 kN, acting downward. - Another vertical load of 6.8 kN is acting downward at point \( G \). - The structure is supported at two points: - At point \( A \), there are two reaction forces: \( A_x \) (horizontal) pointing to the left and \( A_y \) (vertical) pointing upwards. - At point \( F \), there is a vertical reaction force \( F_y \) pointing upwards. - The distances between specific points are marked, with horizontal distances \( AB, BC, CD, DE, \) and \( EF \) each equal to 2 m, and \( BG \) and \( GE \) each equal to 3 m. The diagram helps in analyzing the forces and reactions in the structure to ensure it remains in equilibrium.
Transcribed Image Text:**Text for Educational Website:** Because every joint has more than two unknowns, we will begin by solving for the external reactions. The free-body diagram of the entire structure is shown. Calculate \( A_x, A_y, \) and \( F_y \). **Diagram Explanation:** This is a structural free-body diagram with several forces and dimensions indicated: - The structure is composed of a series of interconnected members forming a shape similar to a truss. - There are vertical loads at points \( C \) and \( D \), each with a magnitude of 7.8 kN, acting downward. - Another vertical load of 6.8 kN is acting downward at point \( G \). - The structure is supported at two points: - At point \( A \), there are two reaction forces: \( A_x \) (horizontal) pointing to the left and \( A_y \) (vertical) pointing upwards. - At point \( F \), there is a vertical reaction force \( F_y \) pointing upwards. - The distances between specific points are marked, with horizontal distances \( AB, BC, CD, DE, \) and \( EF \) each equal to 2 m, and \( BG \) and \( GE \) each equal to 3 m. The diagram helps in analyzing the forces and reactions in the structure to ensure it remains in equilibrium.
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