ve- 37 For the instant represented the particle P has a ve locity v = 6 m/s in the direction shown and has acceleration components ax 15 m/s² and a = -15 m/s². Determine a,, ay, at, and an and the ra- dius of curvature p of the path for this position. (Hint: Draw the related acceleration components of the total acceleration of the particle and take ad- vantage of the simplified geometry for your calculations.) Ans. ar 5√3 m/s², a, 10,3 m/s², p = r=3m 0 = 30° -5√3 m/s², a, <= 0 6√3 30° m x

ve- 37 For the instant represented the particle P has a ve locity v = 6 m/s in the direction shown and has acceleration components ax 15 m/s² and a = -15 m/s². Determine a,, ay, at, and an and the ra- dius of curvature p of the path for this position. (Hint: Draw the related acceleration components of the total acceleration of the particle and take ad- vantage of the simplified geometry for your calculations.) Ans. ar 5√3 m/s², a, 10,3 m/s², p = r=3m 0 = 30° -5√3 m/s², a, <= 0 6√3 30° m x

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

See similar textbooks

Similar questions

The particle P starts from rest at point A at time t = 0 and changes its speed thereafter at a constant rate of 2.3g as it follows the horizontal path shown. Determine the magnitude and direction of its total acceleration at times t = 0.67 s and t = 1.24 s. State your directions relative to the x-axis shown (CCW positive) and choose the angle with the smallest magnitude. P B 3.06 m- 4.02 m Answers: At t = 0.67 s, a = i m/s?, 0 = i Att = 1.24 s, a = m/s?, 0 = i
The particle P starts from rest at point A at time t = 0 and changes its speed thereafter at a constant rate of 2.9g as it follows the horizontal path shown. Determine the magnitude and direction of its total acceleration at timest= 0.78 s and t = 1.09 s. State your directions relative to the x-axis shown (CCW positive) and choose the angle with the smallest magnitude. A. P B -2.71 m- 3.99 m Answers: Att = 0.78 s, a= m/s?. e = i Att = 1.09 s, a = i m/s?, e = i
1. a₂ = == A cart is propelled over an xy plane with acceleration components 4.0 m/s² and ay - 3.0 m/s². Its initial velocity has components or =- 6.0 m/s and voy 5 m/s. If the cart passes the origin at t = 1.0s, what are the x and y coordinates of the cart when it reaches its smallest coordinate?
Given: The train engine at E has a speed of 20 m/s and an acceleration of 14 m/s² acting at v = 20 m/s in the direction shown. a= 14 m/s an Find: The rate of increase in the train's speed and the radius of curvature p of the path.
A car moving with constant speed from point A and sinks to point B of the hump. The radius of curvature of the road at point A is KA=120m and acceleration at A is 0.5g. Determine the car speed V if at point B acceleration is limited to 0.3g. Find the minimum radius of curvature ( KB) of road at point B.
Thex-and y-motions of guides A and Bwith right-angle slots control the curvilinear mation of the connecting pin P. which slides in bath slots. For a short interval, the motions are governed byx- 19+0.47 and y - 19 - 0.90P. wherexand y are in millimeters and tis in seconds. Calculate the magnitudes of the velocity v and acceleration a of the pin for t-23s. Sketch the direction of the path and indicate its curvature for this instant. Calculate the x- and y-components of the acceleration. Answers: mm/s? 0.94 a,- -12.42 mm/s? Calculate the x- and y-components of the velocity. Answers: 2.162 mm/s Vy" -14.283 mm/s
The particle P starts from rest at point A at time t = 0 and changes its speed thereafter at a constant rate of 1.9g as it follows the horizontal path shown. Determine the magnitude and direction of its total acceleration at times t = 0.69 s and t= 1.32 s. State your directions relative to the x-axis shown (CCW positive) and choose the angle with the smallest magnitude. B - 2.53 m- 3.62 m Answers: Att = 0.69 s, a = i 18.639 m/s?, i Att = 1.32 s, a= m/s?, e-
A particle moves on a circular path of 20 ft radius so thatits arc distance from a fixed point on the path is given by s= 4t3 -10t where s is in feet and t in seconds. Compute thetotal acceleration at the end of 2 seconds. plss inlude the free body diagram ty..
Please include explanation. The car has a forward acceleration of a= 4.888m/s2 without slipping its 647-millimeter diameter tires. Determine (a) the velocity v of the car when point P at the tire (corresponding to theta= 48 degree as shown) has zero horizontal component of acceleration. Also, compute for (b) the total acceleration at point P. NOTE: Use purely RMA Method for velocity and acceleration calculations.
The particle P starts from rest at point A at time t = 0 and changes its speed thereafter at a constant rate of 1.7g as it follows the horizontal path shown. Determine the magnitude and direction of its total acceleration at times t = 0.79 s and t = 1.45 s. State your directions relative to the x-axis shown (CCW positive) and choose the angle with the smallest magnitude. B + 3.17 m- 3.90 m Answers: At t = 0.79 s, a = 47.523 m/s?, e = -98.5 At t = 1.45 s, a = 16.677 m/s?, e = 180
A particle moves along a circular path of radius r = 350mm. If its angular velocity is 0 31² where t is in seconds, determine the magnitude of the particle's acceleration when @=45°. The particle starts from rest when 0 0° Select one: O A. a = 2.57 m/s² ÓB. a = 3.4 m/s² OC. a = 2.99 m/s² OD ar 3.97 m/s2 O A
(b) At the apex, determine the speed vof the ball, the total acceleration a of the ball, the normal component of acceleration an and the tangential component of acceleration a. Answers: V = i ft/sec ft/sec? an = ft/sec? dt = ft/sec2