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ve- 37 For the instant represented the particle P has a ve locity v = 6 m/s in the direction shown and has acceleration components ax 15 m/s² and a = -15 m/s². Determine a,, ay, at, and an and the ra- dius of curvature p of the path for this position. (Hint: Draw the related acceleration components of the total acceleration of the particle and take ad- vantage of the simplified geometry for your calculations.) Ans. ar 5√3 m/s², a, 10,3 m/s², p = r=3m 0 = 30° -5√3 m/s², a, <= 0 6√3 30° m x

ve- 37 For the instant represented the particle P has a ve locity v = 6 m/s in the direction shown and has acceleration components ax 15 m/s² and a = -15 m/s². Determine a,, ay, at, and an and the ra- dius of curvature p of the path for this position. (Hint: Draw the related acceleration components of the total acceleration of the particle and take ad- vantage of the simplified geometry for your calculations.) Ans. ar 5√3 m/s², a, 10,3 m/s², p = r=3m 0 = 30° -5√3 m/s², a, <= 0 6√3 30° m x

Elements Of Electromagnetics
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
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2/237 For the instant represented the particle P has a ve- locity v 6 m/s in the direction shown and has acceleration components a = 15 m/s² and a = -15 m/s². Determine a,, a, a, and an and the ra- dius of curvature p of the path for this position. (Hint: Draw the related acceleration components of the total acceleration of the particle and take ad- vantage of the simplified geometry for your calculations.) Ans. a, 5√3 m/s², a, = 10/3 m/s², p an = r=3m 0 = 30° 8 Problem 2/237 -5√/3 m/s², a, <= 0 6√3 5 30° m
Transcribed Image Text:2/237 For the instant represented the particle P has a ve- locity v 6 m/s in the direction shown and has acceleration components a = 15 m/s² and a = -15 m/s². Determine a,, a, a, and an and the ra- dius of curvature p of the path for this position. (Hint: Draw the related acceleration components of the total acceleration of the particle and take ad- vantage of the simplified geometry for your calculations.) Ans. a, 5√3 m/s², a, = 10/3 m/s², p an = r=3m 0 = 30° 8 Problem 2/237 -5√/3 m/s², a, <= 0 6√3 5 30° m
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