A common-emitter amplifier similar to as shown is operating from a single +20-V power supply, and the emitter terminal is bypassed by capacitor C3. The BJT has βF =100 and VA=50 V and is operating at a Q-point of (100 μA, 10 V). The amplifier has RI = 5 kΩ, RB = 150 kΩ, RC = 100 kΩ, and R3 = ∞. What is the voltage gain predicted using our rule of thumb estimate? What is the actual voltage gain? What is the value of μf for this transistor? +Vcc = 12 VR2RcRCEout300 k222 k2inR3RỊ00voR11 k2100 k2R1RE1 k2RCR3 .3 k2Rg = R,|| R2.RE104 k2Signal160 k222 kQ100 k2C3→00source3 k2R410 k2(b)(a)RIR1| RiBRcR3 .RgU beRgUbe8mUbe8m UbeRERERL(d)(c)Figure 14.7 (a) Common-emitter amplifier circuit employing a bipolar transistor; (b) ac equivalent circuit for the common-emitter amplifier in part (a); the common-emitter connection should now be evident; (c) ac equivalent circuit with thebipolar transistor replaced by its small-signal model; (d) final equivalent circuit for ac analysis of the common-emitteramplifier in which r, has been neglected.

Calculating voltage gain of the common emitter amplifier AVCE≅-10VCCAVCE≅-10×20AVCE≅-200 Value of…

Answered: +Vcc = 12 V R2 Rc RCE out 300 k2 22 k2…

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

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A common-emitter amplifier similar to as shown is operating from a single +20-V power supply, and the emitter terminal is bypassed by capacitor C₃. The BJT has β_F =100 and V_A=50 V and is operating at a Q-point of (100 μA, 10 V). The amplifier has R_I = 5 kΩ, R_B = 150 kΩ, R_C = 100 kΩ, and R₃ = ∞. What is the voltage gain predicted using our rule of thumb estimate? What is the actual voltage gain? What is the value of μ_f for this transistor?

+Vcc = 12 V
R2
Rc
RCE
out
300 k2
22 k2
in
R3
RỊ
00
vo
R1
1 k2
100 k2
R1
RE
1 k2
RC
R3 .
3 k2
Rg = R,|| R2.
RE
104 k2
Signal
160 k2
22 kQ
100 k2
C3→00
source
3 k2
R4
10 k2
(b)
(a)
RI
R1
| RiB
Rc
R3 .
Rg
U be
Rg
Ube
8mUbe
8m Ube
RE
RE
RL
(d)
(c)
Figure 14.7 (a) Common-emitter amplifier circuit employing a bipolar transistor; (b) ac equivalent circuit for the common-
emitter amplifier in part (a); the common-emitter connection should now be evident; (c) ac equivalent circuit with the
bipolar transistor replaced by its small-signal model; (d) final equivalent circuit for ac analysis of the common-emitter
amplifier in which r, has been neglected.

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