Solve 10,11,12 Value1) Req2) Veg3) IB4) IE5) Ic6) VCE7) VE8) VB9) re10) 9m11) T12) Zin13) Zout14) Vaut15) Av(₁ + 2/2)^-1R2R2R1 + R2(ß + 1) * IBIB* B-Veq+ Req*IB+ Vbe +Re [ (ß +1) *IB]=0IE*REVBE+VE* Vcc-VCC+ VCE+RC (IC) +RE (IE) = 0VTIE(IC)(VT)(B)(9m)Rin=VoutVsig(rn)(B+1)RC (RL)Rout=-B(B+1) Rin+RsigTable 3EquationsRC+(RL)-Rin(Vsig)RC* (RL)RC+(RL)Final Value For the below CB amplifier circuit:C510uR1101kR211.2k12VBE=0.63VAIHE0VCCwwQ1wwwFigure 1.RC12kQ2N39040RE1kC3HI16uRsig0 B=100Thermal Voltage VT=26mV, Vsig=10m V.50C4HH10uVinVOFF = 0VAMPL = 10mFREQ = 10kAC =V1VoutCalculate the DC bias Analysis and using the values you found for the small signalparameters. Record the calculated input and output voltages in Table 3.Given that:2.6k

Value 1) Req 2) Veg 3) IB 4) IE 5) Ic 6) VCE 7) VE 8) VB 9) re 10) 9m 11) T 12) Zin 13) Zout 14) Vaut 15) Av (12+12/25 ^-1 R1 R2 R1 + R2 (B+1) * IB IB* B -Veg+ Req*IB+ Vbe +Re [ (ß +1) *IB]=0 IE*RE VBE+VE VT IE (IC) * Vcc -VCC+ VCE+RC (IC) +RE (IE) = 0 (VT) (B) (9m) Rin= Rout= -ß (B+1) Vout Vsig (rn) (B+1) Table 3 RC (RL) Equations RC+(RL) -Rin Rin+Rsig re RC (RL). (Vsig) (RC+(RL) Final Value

Value 1) Req 2) Veg 3) IB 4) IE 5) Ic 6) VCE 7) VE 8) VB 9) re 10) 9m 11) T 12) Zin 13) Zout 14) Vaut 15) Av (12+12/25 ^-1 R1 R2 R1 + R2 (B+1) * IB IB* B -Veg+ ReqIB+ Vbe +Re [ (ß +1) IB]=0 IERE VBE+VE VT IE (IC) Vcc -VCC+ VCE+RC (IC) +RE (IE) = 0 (VT) (B) (9m) Rin= Rout= -ß (B+1) Vout Vsig (rn) (B+1) Table 3 RC (RL) Equations RC+(RL) -Rin Rin+Rsig re RC (RL). (Vsig) (RC+(RL) Final Value

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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