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valuation) methods discovers a damage: a half-circular surface crack of size a = 5 mm . ngineer Ben wants to replace e damaged part with a new one, ut a replacement part is not nmediately available. Hence, ne cracked part is still being sed in the machine to support e tensile load P. Engineer Ben K = FS/na For tensile load P For bending load M P 3M S = S, = 2bt S = Sp : bt² %3D F = F, = 0.728 F = F, = 0.728 rants to make sure that the Stress intensity factor for half-circular surface crack (textbook, Fig racked part is safe, so he adds a

valuation) methods discovers a damage: a half-circular surface crack of size a = 5 mm . ngineer Ben wants to replace e damaged part with a new one, ut a replacement part is not nmediately available. Hence, ne cracked part is still being sed in the machine to support e tensile load P. Engineer Ben K = FS/na For tensile load P For bending load M P 3M S = S, = 2bt S = Sp : bt² %3D F = F, = 0.728 F = F, = 0.728 rants to make sure that the Stress intensity factor for half-circular surface crack (textbook, Fig racked part is safe, so he adds a

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Fracture Mechanics
A machine part (see Figure) with outer dimension of tx 2b (t = 50 mm, b = 25 mm) is designed to support a tensile force P = 70 kN in the machine. In a safety inspection, NDE (Nondestructive Evaluation) methods discovers a damage: a half-circular surface crack of size a = 5 mm . Engineer Ben wants to replace the damaged part with a new one, but a replacement part is not immediately available. Hence, the cracked part is still being used in the machine to support the tensile load P. Engineer Ben K = FSTA For tensile load P For bending load M 3M S = S, = 2bt S = S, = bt2 F = F; = 0.728 F = F, = 0.728 wants to make sure that the Stress intensity factor for half-circular surface crack (textbook, Fig 8.17) cracked part is safe, so he adds a bending moment M of negative magnitude, which bends the part in the direction to press the two crack surfaces to close (as against to open the crack to cause fracture). Determine the magnitude of M that will give a safety factor against fracture XK = 2.3 when the cracked part is subjected to both the tensile force P = 70 kN and the bending moment M. The material is ASTM A470-8 steel which has fracture toughness Kic = 60 MPaym.
Transcribed Image Text:A machine part (see Figure) with outer dimension of tx 2b (t = 50 mm, b = 25 mm) is designed to support a tensile force P = 70 kN in the machine. In a safety inspection, NDE (Nondestructive Evaluation) methods discovers a damage: a half-circular surface crack of size a = 5 mm . Engineer Ben wants to replace the damaged part with a new one, but a replacement part is not immediately available. Hence, the cracked part is still being used in the machine to support the tensile load P. Engineer Ben K = FSTA For tensile load P For bending load M 3M S = S, = 2bt S = S, = bt2 F = F; = 0.728 F = F, = 0.728 wants to make sure that the Stress intensity factor for half-circular surface crack (textbook, Fig 8.17) cracked part is safe, so he adds a bending moment M of negative magnitude, which bends the part in the direction to press the two crack surfaces to close (as against to open the crack to cause fracture). Determine the magnitude of M that will give a safety factor against fracture XK = 2.3 when the cracked part is subjected to both the tensile force P = 70 kN and the bending moment M. The material is ASTM A470-8 steel which has fracture toughness Kic = 60 MPaym.
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