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VA V₁ = 3V VAD R₁ = 4k R₂=51 RD = 5K RS= 6K Rext = 20K VG = 1.67V sing formula Ins= B (VGS-Vz) ² 2 be coming Ins= B (VG - IDs Rs - VtJ² IDS= - 20v.

VA V₁ = 3V VAD R₁ = 4k R₂=51 RD = 5K RS= 6K Rext = 20K VG = 1.67V sing formula Ins= B (VGS-Vz) ² 2 be coming Ins= B (VG - IDs Rs - VtJ² IDS= - 20v.

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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•B= 0.01 A/v² V = 0.6V Cgs N negligibly small VA 20v. = V₁ = 3V R₁ = 4K R₂=5K RD = 51 RS= 6K Rext = 20K VG = 1.67V 6 Using formula Ips = B (VGs-V₂) ² be coming IDS= B_ (VG - Ips Rs - V₂ J² Solve the quadratic equation for Ips. How do they get the answer 149 μA and 212μA ²
Transcribed Image Text:•B= 0.01 A/v² V = 0.6V Cgs N negligibly small VA 20v. = V₁ = 3V R₁ = 4K R₂=5K RD = 51 RS= 6K Rext = 20K VG = 1.67V 6 Using formula Ips = B (VGs-V₂) ² be coming IDS= B_ (VG - Ips Rs - V₂ J² Solve the quadratic equation for Ips. How do they get the answer 149 μA and 212μA ²
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