V36V₁ -2.608V3 V3 = 1.62V₁ = 8740. 1256 V₂ = V₁ -0.869 (1.6624) V₂ = 1.44V₁ V₁ = 528. V
V36V₁ -2.608V3 V3 = 1.62V₁ = 8740. 1256 V₂ = V₁ -0.869 (1.6624) V₂ = 1.44V₁ V₁ = 528. V
Related questions
Question
i need the answer quickly
Transcribed Image Text:V₁ = 5258.8 V
V₂ = 6047.61 v
7743.583
V3
(efficiency)
= 82%
m
→>>
=
V
19050
3(7743.683)
arrow_forward
Step 2
V₂ = 1.44V₁
V₁ = 528. V
solution (2)
After the guard ring
0.2c,0.15c
At part A
Cv₂ +0.15 (V₂ + V3) = CV₁ +0.15(
1. 15V2 + V3 = 1.15V₁
1.15V₁-V3
1.15
0.15 (V₁)
V₂ =
V2 = V₁ -0.869V3
At point B
Cv3 +0.2Cv3 = Cv3 +0.15 (V3+ V2 +1
+ V₁)
5 (V₂ + V₁)
0.23V3 -0.15V3 = 0.15 (V₂ +
0.05V/3 3= 0.15 (V₁ + V₁ -0.869V/3)
V36V₁ -2.608V3
V3 = 1.62V₁
=8740. 1256
V₂ = V₁ – 0.869 (1.6624)
How did he get the
value inside the circle
Expert Solution
This question has been solved!
Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.
Step by step
Solved in 2 steps
