V2 (3) + Vs (2j) = V2 + 2V3 = - 1). Step-2: By applsing Analy sis at Nodal V3 : V3 - V2 V3 V3 - 60C30° -4 jio - ju V, Jio -4 - 60L30" 8 32+ 60C3 %3D 10 Vs (-4i+ 103 + 5) + V2 (u) 32 + S1.96 +. V3 ( 5+63) + Vz (ui) = s[ 83.96 + j30). V3 (s+6] + vz (ui) = 419.8+ jiso + V2 (4L90")= 4us.79 (19.66 ° B solviva e9.. (2) 4 (3): get we - 87.895 -j 279.862 293 34 L25?.56°V - 8.01 + j I09.931 Vマ: 110. 22 /94r167° v volkage values are v, = 60L30° u; 293. 34 (252.56°v V3 = 110.22 94.167 v Hence solved

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