V1,f V2,f = - (m₁ — m²)v₁,i + 2m2v2,i m1 + m2 (m2 — m₁)v2,i + 2m₁V1,i - m1 + m2 (7) (8) For inelastic collisions, energy conservation [or Eq. (6)] does not apply. In general, momentum conservation [or Eq. (5)] itself cannot determine the two final velocities without more details be- ing given. However, there is a special case called a completely inelastic collision, in which the two objects stick together and move as one object after the collision. The two objects thus have the same final velocity, V₁₁f = V2,f = Vf. Combining this relation and Eq. (5), one obtains Vƒ m1v1,i+m2v2,i m1 + m2 (9)
V1,f V2,f = - (m₁ — m²)v₁,i + 2m2v2,i m1 + m2 (m2 — m₁)v2,i + 2m₁V1,i - m1 + m2 (7) (8) For inelastic collisions, energy conservation [or Eq. (6)] does not apply. In general, momentum conservation [or Eq. (5)] itself cannot determine the two final velocities without more details be- ing given. However, there is a special case called a completely inelastic collision, in which the two objects stick together and move as one object after the collision. The two objects thus have the same final velocity, V₁₁f = V2,f = Vf. Combining this relation and Eq. (5), one obtains Vƒ m1v1,i+m2v2,i m1 + m2 (9)
Related questions
Question
![V1,f
=
V2,f
-
(m₁ — m²)v₁,i + 2m2V2,i
m1 + m2
(m2 — m₁)v2,i + 2m₁V1,i
-
m1 + m2
(7)
(8)
For inelastic collisions, energy conservation [or Eq. (6)] does not apply. In general, momentum
conservation [or Eq. (5)] itself cannot determine the two final velocities without more details be-
ing given. However, there is a special case called a completely inelastic collision, in which the two
objects stick together and move as one object after the collision. The two objects thus have the
same final velocity, V₁₁f = V2,f = Vf. Combining this relation and Eq. (5), one obtains
Vf
m1v1,i+m2v2,i
m1 + m2
(9)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F862db61d-534e-437e-95a4-fb0436768673%2F54035045-1781-4419-a1dc-41332fd7f872%2Fcte9pc7_processed.png&w=3840&q=75)
Transcribed Image Text:V1,f
=
V2,f
-
(m₁ — m²)v₁,i + 2m2V2,i
m1 + m2
(m2 — m₁)v2,i + 2m₁V1,i
-
m1 + m2
(7)
(8)
For inelastic collisions, energy conservation [or Eq. (6)] does not apply. In general, momentum
conservation [or Eq. (5)] itself cannot determine the two final velocities without more details be-
ing given. However, there is a special case called a completely inelastic collision, in which the two
objects stick together and move as one object after the collision. The two objects thus have the
same final velocity, V₁₁f = V2,f = Vf. Combining this relation and Eq. (5), one obtains
Vf
m1v1,i+m2v2,i
m1 + m2
(9)
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