V16._ lis distance from the ground at t seconds is given by s(t) = -16t2 + 64t + 144. How fast is the ball moving 2 seconds after being thrown? A ball is thrown vertically upward from the ground at a velocity of 64 ft per second. V(t) = sTt) =16(2+)+ L04 + 144 =-32t + 64+144 S'lt) %3D (a) 0 ft per second (b) 2 ft per second -32(2) +64+144 144 () 208 ft per = secund -164 +64 + 144 {d) 44 T per ·second (e) None of tbe Above

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