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V=10.om/s 12. A 2000-kg car has a velocity of 12.0 m/s. The car then hits a tree. The tree doesn't move and the car comes to rest. a. Find the change in kinetic energy of the car. n=7000 K V= 17.6 nl5 b. Find the amount of work done in pushing in the front of the car. て KE= " KE = (7000) (12-0)-4320J %3D A c. Find the size of the force that pushed in the front of the car in 0.50 m.

V=10.om/s 12. A 2000-kg car has a velocity of 12.0 m/s. The car then hits a tree. The tree doesn't move and the car comes to rest. a. Find the change in kinetic energy of the car. n=7000 K V= 17.6 nl5 b. Find the amount of work done in pushing in the front of the car. て KE= " KE = (7000) (12-0)-4320J %3D A c. Find the size of the force that pushed in the front of the car in 0.50 m.

College Physics
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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KE=4 muž GPE = mgh Perto レ=fd Wnat-DKE Energy Directions: Read each of the following statements/questions. Answer them correctly 1 A shot-putter heaves a 7.26-kg shot with a final velocity of 7.50 m/s. a. What is the kinetic energy if the shot? m= 7.26 K9 V= 7.50 m/s KE -nu KE .26X7.50)= |204.2J b. The shot was initially at rest. How much work was done on it to give it this kinetic energy? W=KEF wZ64.2J) 2. What is the kinetic energy of a 750-kg compact car traveling at 27.0 m/s? me 750 kg V= 27.0 mls 3. A 2.00-kg textbook is lifted from the floor to a shelf 2.10 m above the floor. a. What is the gravitational potential energy relative to the floor? KE =4. ? KE 4)(750) (27)2 273375, J m= 2.00 SPE=rgh aPE : (7.6) ( 9.8) (2-10) - t1.2 b. What is the gravitational potential energy relative to the head of a 1.65 m tall person? 7.16-1.65:-75 GPE = (7-0)(98) (.45)=8.8J) A 90-kg rock climber first climb 45 m upward to the top edge of a quarry, then, from the top, descends 85 m to the bottom. Find the potential energy of the climber at the edge and at the bottom, using the initial height as the reference level. 5. A 50.0-kg shell is shot from a cannon at Earth's surface to a height of 400 m. What is the gravitational potential energy with respect to Earth's surface of the Earth-shell system when the shell is at this height? GPE = mgh m= Se0 a. GPE= (50.0) ( 9.8) (400) = 196660-J 9-9.8 h=400 b. What is the change in potential energy of the system when the shell falls to a height of 200 m? GPE= (50.0) (9.8) (Zoo) = 6. A person weighing 630-N climbs up a ladder to a height of 5.0m. 198600.J) a. What work does the person do? f=630MFd w=(630) (5.0) = 3150.J d= 5.om wr b. What is the increase in the gravitational potential energy of the person from the ground to this height? GPE = Fd Same thing 7. A 1600-kg car travels at a speed of 12.5 m/s. What is its kinetic energy? m=1600 KJ V= 17.5 m/s KE = ZC 1600) C12.5)? 1800.J 8. A racing car has a mass of 1500-kg. What is its kinetic energy if it has a speed of 30.0 m/s? m=1500 Kg V- 30,0mls KEmoe KE= (1500)( 30 0)2 V= 3o,0m/s 675000.5 11) 27 = 3 15) 212 = 4+,
Transcribed Image Text:KE=4 muž GPE = mgh Perto レ=fd Wnat-DKE Energy Directions: Read each of the following statements/questions. Answer them correctly 1 A shot-putter heaves a 7.26-kg shot with a final velocity of 7.50 m/s. a. What is the kinetic energy if the shot? m= 7.26 K9 V= 7.50 m/s KE -nu KE .26X7.50)= |204.2J b. The shot was initially at rest. How much work was done on it to give it this kinetic energy? W=KEF wZ64.2J) 2. What is the kinetic energy of a 750-kg compact car traveling at 27.0 m/s? me 750 kg V= 27.0 mls 3. A 2.00-kg textbook is lifted from the floor to a shelf 2.10 m above the floor. a. What is the gravitational potential energy relative to the floor? KE =4. ? KE 4)(750) (27)2 273375, J m= 2.00 SPE=rgh aPE : (7.6) ( 9.8) (2-10) - t1.2 b. What is the gravitational potential energy relative to the head of a 1.65 m tall person? 7.16-1.65:-75 GPE = (7-0)(98) (.45)=8.8J) A 90-kg rock climber first climb 45 m upward to the top edge of a quarry, then, from the top, descends 85 m to the bottom. Find the potential energy of the climber at the edge and at the bottom, using the initial height as the reference level. 5. A 50.0-kg shell is shot from a cannon at Earth's surface to a height of 400 m. What is the gravitational potential energy with respect to Earth's surface of the Earth-shell system when the shell is at this height? GPE = mgh m= Se0 a. GPE= (50.0) ( 9.8) (400) = 196660-J 9-9.8 h=400 b. What is the change in potential energy of the system when the shell falls to a height of 200 m? GPE= (50.0) (9.8) (Zoo) = 6. A person weighing 630-N climbs up a ladder to a height of 5.0m. 198600.J) a. What work does the person do? f=630MFd w=(630) (5.0) = 3150.J d= 5.om wr b. What is the increase in the gravitational potential energy of the person from the ground to this height? GPE = Fd Same thing 7. A 1600-kg car travels at a speed of 12.5 m/s. What is its kinetic energy? m=1600 KJ V= 17.5 m/s KE = ZC 1600) C12.5)? 1800.J 8. A racing car has a mass of 1500-kg. What is its kinetic energy if it has a speed of 30.0 m/s? m=1500 Kg V- 30,0mls KEmoe KE= (1500)( 30 0)2 V= 3o,0m/s 675000.5 11) 27 = 3 15) 212 = 4+,
13) 9. Sally has a mass if 45-kg and is moving with a speed of 10.0 m/s. a. Find Sally's kinetic energy. (45)(l0) (2250.5) KE = + mvz KE V= 1B. Sally's speed changes to 5.0 m/s. Now what is her kinetic energy? m=45K9" KE =5nv V C. HOW much work was done to change her speed? 562.5J) KE=5 (45)(5)? 2250: 10. Shawn and his bike have a total mass of 45.0-kg, Shawn rides 1800 m in 600 seconds at a constant velocity. What is Shawn's kinetic energy? 1800-606 -3 KE =Ś (45)(3)" (20253) KE = mvz 11 11. Matt and Will each have a mass of 60-kg and they are moving together with a velocity of 10.0 m/s. What is their combined kinețic energy? n=6o K9 V=10.om/s 12. A 2000-kg car has a velocity of 12.0 m/s. The car then hits a tree. The tree doesn't move and the car KE- KE = ( 60) Clo) 3000.) comes to rest. a. Find the change in kinetic energy of the car. n- 7000 K) V= 17.6 nl5 b. Find the amount of work done in pushing in the front of the car. KE= mv? KE= (7000) (12:0)-(4320J c. Find the size of the force that pushed in the front of the car in 0.50 m. 13. How much potential energy does Tim, mass 60.0-kg, gain when he climbs a gymnasium rope a distance 66 of 3.5 m? GPE=ngh GPE = (60) ( 9.)3.5)= 9= 9.8 2058.3 14. A 6.4-kg bowling ball is lifted 2.1 m into a storage rack. Calculate the increase in the ball's potential energy. m= 6.4 K9 9=9.8 15. Mary weighs 500-N and walks down a flight of stairs to a level 5.50 m below her starting point, What is the change in Mary's potential energy? E= 500 N d- 5.5am 16. Å weightlifter raises a 180-kg barbell to a height of 1.95 m. What is the increase in the barbell's potential energy? m=180 K9 GPE = mgh GPE = (6.4) (9.8) (2-1) 131.712J (500) (5.50)= 2750J g-9.8 GPE= mgh OPE = C180)(9-8) (1-98) 3492.72J 17. A 10.0-kg rocket is fired vertically from Cape Canaveral. Its fuel gives it a kinetic energy of 1960 J by the time the rocket motor burns out of fuel. What additional height will the rocket rise? 18. A hallway of energy is constructed. People are told that to do 1.00 J of work, they should pull on a rope that lifts a block 1.00 m. What should be the mass of the block?
Transcribed Image Text:13) 9. Sally has a mass if 45-kg and is moving with a speed of 10.0 m/s. a. Find Sally's kinetic energy. (45)(l0) (2250.5) KE = + mvz KE V= 1B. Sally's speed changes to 5.0 m/s. Now what is her kinetic energy? m=45K9" KE =5nv V C. HOW much work was done to change her speed? 562.5J) KE=5 (45)(5)? 2250: 10. Shawn and his bike have a total mass of 45.0-kg, Shawn rides 1800 m in 600 seconds at a constant velocity. What is Shawn's kinetic energy? 1800-606 -3 KE =Ś (45)(3)" (20253) KE = mvz 11 11. Matt and Will each have a mass of 60-kg and they are moving together with a velocity of 10.0 m/s. What is their combined kinețic energy? n=6o K9 V=10.om/s 12. A 2000-kg car has a velocity of 12.0 m/s. The car then hits a tree. The tree doesn't move and the car KE- KE = ( 60) Clo) 3000.) comes to rest. a. Find the change in kinetic energy of the car. n- 7000 K) V= 17.6 nl5 b. Find the amount of work done in pushing in the front of the car. KE= mv? KE= (7000) (12:0)-(4320J c. Find the size of the force that pushed in the front of the car in 0.50 m. 13. How much potential energy does Tim, mass 60.0-kg, gain when he climbs a gymnasium rope a distance 66 of 3.5 m? GPE=ngh GPE = (60) ( 9.)3.5)= 9= 9.8 2058.3 14. A 6.4-kg bowling ball is lifted 2.1 m into a storage rack. Calculate the increase in the ball's potential energy. m= 6.4 K9 9=9.8 15. Mary weighs 500-N and walks down a flight of stairs to a level 5.50 m below her starting point, What is the change in Mary's potential energy? E= 500 N d- 5.5am 16. Å weightlifter raises a 180-kg barbell to a height of 1.95 m. What is the increase in the barbell's potential energy? m=180 K9 GPE = mgh GPE = (6.4) (9.8) (2-1) 131.712J (500) (5.50)= 2750J g-9.8 GPE= mgh OPE = C180)(9-8) (1-98) 3492.72J 17. A 10.0-kg rocket is fired vertically from Cape Canaveral. Its fuel gives it a kinetic energy of 1960 J by the time the rocket motor burns out of fuel. What additional height will the rocket rise? 18. A hallway of energy is constructed. People are told that to do 1.00 J of work, they should pull on a rope that lifts a block 1.00 m. What should be the mass of the block?
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