V=10.om/s 12. A 2000-kg car has a velocity of 12.0 m/s. The car then hits a tree. The tree doesn't move and the car comes to rest. a. Find the change in kinetic energy of the car. n=7000 K V= 17.6 nl5 b. Find the amount of work done in pushing in the front of the car. て KE= " KE = (7000) (12-0)-4320J %3D A c. Find the size of the force that pushed in the front of the car in 0.50 m.
V=10.om/s 12. A 2000-kg car has a velocity of 12.0 m/s. The car then hits a tree. The tree doesn't move and the car comes to rest. a. Find the change in kinetic energy of the car. n=7000 K V= 17.6 nl5 b. Find the amount of work done in pushing in the front of the car. て KE= " KE = (7000) (12-0)-4320J %3D A c. Find the size of the force that pushed in the front of the car in 0.50 m.
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
Related questions
Question
Number 12
![KE=4 muž
GPE = mgh
Perto
レ=fd
Wnat-DKE Energy
Directions: Read each of the following statements/questions. Answer them correctly
1
A shot-putter heaves a 7.26-kg shot with a final velocity of 7.50 m/s.
a. What is the kinetic energy if the shot?
m= 7.26 K9
V= 7.50 m/s
KE -nu
KE .26X7.50)= |204.2J
b. The shot was initially at rest. How much work was done on it to give it this kinetic energy?
W=KEF wZ64.2J)
2. What is the kinetic energy of a 750-kg compact car traveling at 27.0 m/s?
me 750 kg
V= 27.0 mls
3. A 2.00-kg textbook is lifted from the floor to a shelf 2.10 m above the floor.
a. What is the gravitational potential energy relative to the floor?
KE =4.
? KE 4)(750) (27)2
273375, J
m= 2.00
SPE=rgh aPE : (7.6) ( 9.8) (2-10) - t1.2
b. What is the gravitational potential energy relative to the head of a 1.65 m tall person? 7.16-1.65:-75
GPE = (7-0)(98) (.45)=8.8J)
A 90-kg rock climber first climb 45 m upward to the top edge of a quarry, then, from the top, descends
85 m to the bottom. Find the potential energy of the climber at the edge and at the bottom, using the
initial height as the reference level.
5. A 50.0-kg shell is shot from a cannon at Earth's surface to a height of 400 m.
What is the gravitational potential energy with respect to Earth's surface of the Earth-shell
system when the shell is at this height?
GPE = mgh
m= Se0 a.
GPE= (50.0) ( 9.8) (400) =
196660-J
9-9.8
h=400
b. What is the change in potential energy of the system when the shell falls to a height of 200 m?
GPE= (50.0) (9.8) (Zoo) =
6. A person weighing 630-N climbs up a ladder to a height of 5.0m.
198600.J)
a. What work does the person do?
f=630MFd w=(630) (5.0) = 3150.J
d= 5.om wr
b. What is the increase in the gravitational potential energy of the person from the ground to this
height?
GPE = Fd
Same thing
7. A 1600-kg car travels at a speed of 12.5 m/s. What is its kinetic energy?
m=1600 KJ
V= 17.5 m/s
KE = ZC 1600) C12.5)?
1800.J
8. A racing car has a mass of 1500-kg. What is its kinetic energy if it has a speed of 30.0 m/s?
m=1500 Kg
V- 30,0mls KEmoe KE= (1500)( 30 0)2
V= 3o,0m/s
675000.5
11) 27 = 3
15) 212 = 4+,](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fc7751a5a-4a85-487a-845a-c3c8bd69aa51%2F6235471c-899c-4660-ae68-aa7f51828d80%2Fgq6s7w_processed.jpeg&w=3840&q=75)
Transcribed Image Text:KE=4 muž
GPE = mgh
Perto
レ=fd
Wnat-DKE Energy
Directions: Read each of the following statements/questions. Answer them correctly
1
A shot-putter heaves a 7.26-kg shot with a final velocity of 7.50 m/s.
a. What is the kinetic energy if the shot?
m= 7.26 K9
V= 7.50 m/s
KE -nu
KE .26X7.50)= |204.2J
b. The shot was initially at rest. How much work was done on it to give it this kinetic energy?
W=KEF wZ64.2J)
2. What is the kinetic energy of a 750-kg compact car traveling at 27.0 m/s?
me 750 kg
V= 27.0 mls
3. A 2.00-kg textbook is lifted from the floor to a shelf 2.10 m above the floor.
a. What is the gravitational potential energy relative to the floor?
KE =4.
? KE 4)(750) (27)2
273375, J
m= 2.00
SPE=rgh aPE : (7.6) ( 9.8) (2-10) - t1.2
b. What is the gravitational potential energy relative to the head of a 1.65 m tall person? 7.16-1.65:-75
GPE = (7-0)(98) (.45)=8.8J)
A 90-kg rock climber first climb 45 m upward to the top edge of a quarry, then, from the top, descends
85 m to the bottom. Find the potential energy of the climber at the edge and at the bottom, using the
initial height as the reference level.
5. A 50.0-kg shell is shot from a cannon at Earth's surface to a height of 400 m.
What is the gravitational potential energy with respect to Earth's surface of the Earth-shell
system when the shell is at this height?
GPE = mgh
m= Se0 a.
GPE= (50.0) ( 9.8) (400) =
196660-J
9-9.8
h=400
b. What is the change in potential energy of the system when the shell falls to a height of 200 m?
GPE= (50.0) (9.8) (Zoo) =
6. A person weighing 630-N climbs up a ladder to a height of 5.0m.
198600.J)
a. What work does the person do?
f=630MFd w=(630) (5.0) = 3150.J
d= 5.om wr
b. What is the increase in the gravitational potential energy of the person from the ground to this
height?
GPE = Fd
Same thing
7. A 1600-kg car travels at a speed of 12.5 m/s. What is its kinetic energy?
m=1600 KJ
V= 17.5 m/s
KE = ZC 1600) C12.5)?
1800.J
8. A racing car has a mass of 1500-kg. What is its kinetic energy if it has a speed of 30.0 m/s?
m=1500 Kg
V- 30,0mls KEmoe KE= (1500)( 30 0)2
V= 3o,0m/s
675000.5
11) 27 = 3
15) 212 = 4+,
![13)
9. Sally has a mass if 45-kg and is moving with a speed of 10.0 m/s.
a. Find Sally's kinetic energy.
(45)(l0)
(2250.5)
KE = + mvz
KE
V= 1B. Sally's speed changes to 5.0 m/s. Now what is her kinetic energy?
m=45K9"
KE =5nv
V C. HOW much work was done to change her speed?
562.5J)
KE=5 (45)(5)?
2250:
10. Shawn and his bike have a total mass of 45.0-kg, Shawn rides 1800 m in 600 seconds at a constant
velocity. What is Shawn's kinetic energy?
1800-606 -3
KE =Ś (45)(3)" (20253)
KE = mvz
11
11. Matt and Will each have a mass of 60-kg and they are moving together with a velocity of 10.0 m/s.
What is their combined kinețic energy?
n=6o K9
V=10.om/s
12. A 2000-kg car has a velocity of 12.0 m/s. The car then hits a tree. The tree doesn't move and the car
KE-
KE = ( 60) Clo)
3000.)
comes to rest.
a. Find the change in kinetic energy of the car.
n- 7000 K)
V= 17.6 nl5
b. Find the amount of work done in pushing in the front of the car.
KE= mv? KE= (7000) (12:0)-(4320J
c.
Find the size of the force that pushed in the front of the car in 0.50 m.
13. How much potential energy does Tim, mass 60.0-kg, gain when he climbs a gymnasium rope a distance
66 of 3.5 m?
GPE=ngh
GPE = (60) ( 9.)3.5)=
9= 9.8
2058.3
14. A 6.4-kg bowling ball is lifted 2.1 m into a storage rack. Calculate the increase in the ball's potential
energy.
m= 6.4 K9
9=9.8
15. Mary weighs 500-N and walks down a flight of stairs to a level 5.50 m below her starting point, What is
the change in Mary's potential energy?
E= 500 N
d- 5.5am
16. Å weightlifter raises a 180-kg barbell to a height of 1.95 m. What is the increase in the barbell's
potential energy? m=180 K9
GPE = mgh
GPE = (6.4) (9.8) (2-1)
131.712J
(500) (5.50)= 2750J
g-9.8
GPE= mgh OPE = C180)(9-8) (1-98) 3492.72J
17. A 10.0-kg rocket is fired vertically from Cape Canaveral. Its fuel gives it a kinetic energy of 1960 J by
the time the rocket motor burns out of fuel. What additional height will the rocket rise?
18. A hallway of energy is constructed. People are told that to do 1.00 J of work, they should pull on a rope
that lifts a block 1.00 m. What should be the mass of the block?](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fc7751a5a-4a85-487a-845a-c3c8bd69aa51%2F6235471c-899c-4660-ae68-aa7f51828d80%2Fvvdioc5_processed.jpeg&w=3840&q=75)
Transcribed Image Text:13)
9. Sally has a mass if 45-kg and is moving with a speed of 10.0 m/s.
a. Find Sally's kinetic energy.
(45)(l0)
(2250.5)
KE = + mvz
KE
V= 1B. Sally's speed changes to 5.0 m/s. Now what is her kinetic energy?
m=45K9"
KE =5nv
V C. HOW much work was done to change her speed?
562.5J)
KE=5 (45)(5)?
2250:
10. Shawn and his bike have a total mass of 45.0-kg, Shawn rides 1800 m in 600 seconds at a constant
velocity. What is Shawn's kinetic energy?
1800-606 -3
KE =Ś (45)(3)" (20253)
KE = mvz
11
11. Matt and Will each have a mass of 60-kg and they are moving together with a velocity of 10.0 m/s.
What is their combined kinețic energy?
n=6o K9
V=10.om/s
12. A 2000-kg car has a velocity of 12.0 m/s. The car then hits a tree. The tree doesn't move and the car
KE-
KE = ( 60) Clo)
3000.)
comes to rest.
a. Find the change in kinetic energy of the car.
n- 7000 K)
V= 17.6 nl5
b. Find the amount of work done in pushing in the front of the car.
KE= mv? KE= (7000) (12:0)-(4320J
c.
Find the size of the force that pushed in the front of the car in 0.50 m.
13. How much potential energy does Tim, mass 60.0-kg, gain when he climbs a gymnasium rope a distance
66 of 3.5 m?
GPE=ngh
GPE = (60) ( 9.)3.5)=
9= 9.8
2058.3
14. A 6.4-kg bowling ball is lifted 2.1 m into a storage rack. Calculate the increase in the ball's potential
energy.
m= 6.4 K9
9=9.8
15. Mary weighs 500-N and walks down a flight of stairs to a level 5.50 m below her starting point, What is
the change in Mary's potential energy?
E= 500 N
d- 5.5am
16. Å weightlifter raises a 180-kg barbell to a height of 1.95 m. What is the increase in the barbell's
potential energy? m=180 K9
GPE = mgh
GPE = (6.4) (9.8) (2-1)
131.712J
(500) (5.50)= 2750J
g-9.8
GPE= mgh OPE = C180)(9-8) (1-98) 3492.72J
17. A 10.0-kg rocket is fired vertically from Cape Canaveral. Its fuel gives it a kinetic energy of 1960 J by
the time the rocket motor burns out of fuel. What additional height will the rocket rise?
18. A hallway of energy is constructed. People are told that to do 1.00 J of work, they should pull on a rope
that lifts a block 1.00 m. What should be the mass of the block?
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