Homework Help is Here – Start Your Trial Now!
Science
Advanced Physics
V₁ = V₁-Vcm m₂ V1 m₂ + m₂

V₁ = V₁-Vcm m₂ V1 m₂ + m₂

icon
Related questions
Question

could you explain how we got 7.6.12?  I dont understand why we have to substract vcm from v1 in order to get v1bar

system is zero both before and after the collision. Hence, we can write P₁+P₂ = 0 Pí + P₂ = 0 The bars are used to indicate that the quantity in question is referred to the center of mass system. The energy balance equation reads P₁ P² P₁² P1² + +Q 2m₂ 2m, 2m₂ + 2m₁ (7.6.8) We can eliminate p2 and 2 from Equation 7.6.8 by using the momentum relations in Equations 7.6.7a and b. The result, which is conveniently expressed in terms of the reduced mass, is Hence, we have = P₁_P1² (7.6.9) 2μ 2μ The momentum relations, Equations 7.6.7a and b expressed in terms of velocities, read m₁v₁ + m₂ V₂ = 0 m₁v₁ + m₂v₂ = 0 The velocity of the center of mass is (see Equations 7.1.3 and 7.1.4) ✓ cmn = •+Q (7.6.7a) (7.6.7b) miVi m₂ + m₂ V₁ = V₁-Vcm m₂ V1 m₁ + m₂ (7.6.10a) (7.6.10b) (7.6.11) (7.6.12)
Transcribed Image Text:system is zero both before and after the collision. Hence, we can write P₁+P₂ = 0 Pí + P₂ = 0 The bars are used to indicate that the quantity in question is referred to the center of mass system. The energy balance equation reads P₁ P² P₁² P1² + +Q 2m₂ 2m, 2m₂ + 2m₁ (7.6.8) We can eliminate p2 and 2 from Equation 7.6.8 by using the momentum relations in Equations 7.6.7a and b. The result, which is conveniently expressed in terms of the reduced mass, is Hence, we have = P₁_P1² (7.6.9) 2μ 2μ The momentum relations, Equations 7.6.7a and b expressed in terms of velocities, read m₁v₁ + m₂ V₂ = 0 m₁v₁ + m₂v₂ = 0 The velocity of the center of mass is (see Equations 7.1.3 and 7.1.4) ✓ cmn = •+Q (7.6.7a) (7.6.7b) miVi m₂ + m₂ V₁ = V₁-Vcm m₂ V1 m₁ + m₂ (7.6.10a) (7.6.10b) (7.6.11) (7.6.12)
Expert Solution
steps

Step by step

Solved in 2 steps

SEE SOLUTIONCheck out a sample Q&A here
Blurred answer