V = ¾¼R³
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Question
Diameter is 17 cm, find the radius and plug it into the formula in the image and find your volume.
![The formula shown in the image is for the volume \( V \) of a sphere. It is expressed as:
\[ V = \frac{4}{3} \pi R^3 \]
Where:
- \( V \) represents the volume of the sphere.
- \( \pi \) is a constant approximately equal to 3.14159.
- \( R \) is the radius of the sphere.
- The term \( R^3 \) signifies the cube of the radius, indicating that the volume of a sphere is proportional to the cube of its radius.
This equation is fundamental in geometry and finds applications in various scientific fields including physics and engineering.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F4e11b908-ca46-42ce-8e8f-ef6daf153527%2F29bfebf7-03a7-4a24-9908-c1ba6ab10d31%2Fkh0mwe_processed.png&w=3840&q=75)
Transcribed Image Text:The formula shown in the image is for the volume \( V \) of a sphere. It is expressed as:
\[ V = \frac{4}{3} \pi R^3 \]
Where:
- \( V \) represents the volume of the sphere.
- \( \pi \) is a constant approximately equal to 3.14159.
- \( R \) is the radius of the sphere.
- The term \( R^3 \) signifies the cube of the radius, indicating that the volume of a sphere is proportional to the cube of its radius.
This equation is fundamental in geometry and finds applications in various scientific fields including physics and engineering.
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