V {R total voltage L R = 105 L = 192 MH C = 260 uf V = 100 V F = SS Hert2 a) calculate the total Impedance b) calculate the voltage across each component c) the
V {R total voltage L R = 105 L = 192 MH C = 260 uf V = 100 V F = SS Hert2 a) calculate the total Impedance b) calculate the voltage across each component c) the
Introductory Circuit Analysis (13th Edition)
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ISBN:9780133923605
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Thank you in advance. Please make working clear and readable so it easy to understand.
![404
VO
I
{R
L
с
R = 105
L = 192 MH
C = 260 uf
V = 100 v
F = SS Hertz
a) calculate the total impediance
URSE
6) Calculate the voltage across each component
c) the total voltage
d) use these values to construct a phasar diagram to calculate the phase angle
e) Confirm your phate angle is correct by Calculatio
25
20](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fd5e74575-db89-47d8-a53e-4c26222861f4%2F36784c0a-5c88-4469-80b1-d161ea45ee77%2Fh929h7j_processed.jpeg&w=3840&q=75)
Transcribed Image Text:404
VO
I
{R
L
с
R = 105
L = 192 MH
C = 260 uf
V = 100 v
F = SS Hertz
a) calculate the total impediance
URSE
6) Calculate the voltage across each component
c) the total voltage
d) use these values to construct a phasar diagram to calculate the phase angle
e) Confirm your phate angle is correct by Calculatio
25
20
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Follow-up Question
For R you've used 10 instead of 100 ?
also I don't understand why you've put 10+ 55.22 ohms I need the answer in ohms only. Can you show workings similar to that shown in the picture attached
![X
13:23
This document contains ink,
shapes and images that are... more
Task S
1)
1)
b) I =
a) Total Impedance
2 Jet-xa
R=S
=
Engineering Science unit 3 T2
да
250
9.37
= 26.68 amps
So
کئے۔
9.37
= 0.53 X
2
V5=250V
e) cos 0 = 1/2/2
B
Print Layout
VR = 133.4
Science
250V 55 H2
D=57⁰
los MH
c) VR = I=R = 26.68x5 = 133.4
VL = I xixL = 26.68×36.29=968.2✓
Vc = I x xc = 26.68×28.37 = 756.9 V
C
102 uf
XL = 2T+C
XL = 24TfL = 2 TTXS5 ×0.105 = 36.29
V=968.2V
=
2² √²+(36.29-28.17) ² = 9.37
V=VC-VC
co5¹0-534 = 57°
8. Thomps
277x55x162x10-6
V=968.2756.9
Vc =756.9v v = 211.3V
AD
Read Aloud
Print Layout
= 28.37
●●●
Headings](https://content.bartleby.com/qna-images/question/d5e74575-db89-47d8-a53e-4c26222861f4/70f15bdf-ab15-42d7-afa5-66c565426e09/26yr3gs_thumbnail.png)
Transcribed Image Text:X
13:23
This document contains ink,
shapes and images that are... more
Task S
1)
1)
b) I =
a) Total Impedance
2 Jet-xa
R=S
=
Engineering Science unit 3 T2
да
250
9.37
= 26.68 amps
So
کئے۔
9.37
= 0.53 X
2
V5=250V
e) cos 0 = 1/2/2
B
Print Layout
VR = 133.4
Science
250V 55 H2
D=57⁰
los MH
c) VR = I=R = 26.68x5 = 133.4
VL = I xixL = 26.68×36.29=968.2✓
Vc = I x xc = 26.68×28.37 = 756.9 V
C
102 uf
XL = 2T+C
XL = 24TfL = 2 TTXS5 ×0.105 = 36.29
V=968.2V
=
2² √²+(36.29-28.17) ² = 9.37
V=VC-VC
co5¹0-534 = 57°
8. Thomps
277x55x162x10-6
V=968.2756.9
Vc =756.9v v = 211.3V
AD
Read Aloud
Print Layout
= 28.37
●●●
Headings
Solution
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