v² dx + x(xt y) dx = 0 LINE 1 let x= v2, dx = yda+ zdy y2 (ydz + zdv) + xz(vz +Y)dy= 0 vz (vdz t zdv) + v22 (2+) dy=0 yda + zdv + (22+1) dy yda + (22 t 22) dy dz 22+22 but, LINE 2 LINE 3 LINE 4 LINE S LUNE 6 dy LINE 7 2+22 之十2 LINE 8 V2 22+22 2+2 LINE 9 十 ネ十2ノ42 + 2 In (2) - 2 In (z+2) + InV) = C In (a) - In (2+2) + In(y2) = c dr. LINE 10 INE II LINE 12 In = C. LINE 13 C 2+2 LIND 4 /Aヤス yメ LINE 5
v² dx + x(xt y) dx = 0 LINE 1 let x= v2, dx = yda+ zdy y2 (ydz + zdv) + xz(vz +Y)dy= 0 vz (vdz t zdv) + v22 (2+) dy=0 yda + zdv + (22+1) dy yda + (22 t 22) dy dz 22+22 but, LINE 2 LINE 3 LINE 4 LINE S LUNE 6 dy LINE 7 2+22 之十2 LINE 8 V2 22+22 2+2 LINE 9 十 ネ十2ノ42 + 2 In (2) - 2 In (z+2) + InV) = C In (a) - In (2+2) + In(y2) = c dr. LINE 10 INE II LINE 12 In = C. LINE 13 C 2+2 LIND 4 /Aヤス yメ LINE 5
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter7: Analytic Trigonometry
Section7.6: The Inverse Trigonometric Functions
Problem 94E
Related questions
Question
![Identify three (3) lines in error on the
solution of the given differential
equation. The absence of an integral
sign is not considered an error. Please
be extra careful in selecting correct
answers. Points from incorrect answers
will be deducted from points of correct
answers.
² dx + x(x+ v) dy = 0
LINE 1
let x= v2, dx = yda + zdy
y2 (ydz + zdy)+ xz(vz+Y)dx
v2 (vdz + zdv) + v22 (2+o dy =0
vda + zdv + (22+1) dy =
yda +(2^土2)y
dz
22+ 22
レNE 2
LINE 3
LINE 4
LINE E
UNE
%3D
LINE 7
but,
スー+ス
2 (2t2)
2+2
LINE 8
Yz
V2
22+22
2+2
LINE 9
(- + ) dz +
2 In (2) - 2 In (2+2) + InV) = C
In ()- In (2+ 2) + In(y2) = C
dr.
ライ2
LINE 10
LINE II
LINE 12
In
2+2) e
1 ANIT
LIND 4
C
十2
/Aヤス
yメ
LINE 5](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F57d52ddc-f8a2-459e-8c9f-6cde986c42de%2F453ad43b-8703-409b-99cb-1d87a7f57422%2Fiyonvfc_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Identify three (3) lines in error on the
solution of the given differential
equation. The absence of an integral
sign is not considered an error. Please
be extra careful in selecting correct
answers. Points from incorrect answers
will be deducted from points of correct
answers.
² dx + x(x+ v) dy = 0
LINE 1
let x= v2, dx = yda + zdy
y2 (ydz + zdy)+ xz(vz+Y)dx
v2 (vdz + zdv) + v22 (2+o dy =0
vda + zdv + (22+1) dy =
yda +(2^土2)y
dz
22+ 22
レNE 2
LINE 3
LINE 4
LINE E
UNE
%3D
LINE 7
but,
スー+ス
2 (2t2)
2+2
LINE 8
Yz
V2
22+22
2+2
LINE 9
(- + ) dz +
2 In (2) - 2 In (2+2) + InV) = C
In ()- In (2+ 2) + In(y2) = C
dr.
ライ2
LINE 10
LINE II
LINE 12
In
2+2) e
1 ANIT
LIND 4
C
十2
/Aヤス
yメ
LINE 5
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