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V 36- A horizontal curve T1T2. having a radius R = 530 m, is to join two straights intersecting at point I with an angle A and a forward chaining = 2532.325 m. The distance between the tangency points T1 and T2, on the curve, is T1T2 = 174.568 m. Using the theodolite and tape at 15 m intervals of through chaining, find the deflection angle for the first sub-chord.

V 36- A horizontal curve T1T2. having a radius R = 530 m, is to join two straights intersecting at point I with an angle A and a forward chaining = 2532.325 m. The distance between the tangency points T1 and T2, on the curve, is T1T2 = 174.568 m. Using the theodolite and tape at 15 m intervals of through chaining, find the deflection angle for the first sub-chord.

Structural Analysis
Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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V 36-A horizontal curve 1T2. having a radius R 530 m, is to join two straights intersecting at point I with an angle A and a forward chaining = 2532.325 m. The distance between the tangency points 11 and T2, on the curve, is T1T2 174.568 m. Using the theodolite and tape at 15 m intervals of through chaining, find the deflection angle for the first sub-chord.
V 36- A horizontal curve T1T2. having a radius R = 530 m, is to join two straights intersecting at point I with an angle A and a forward chaining 2532.325 m. The distance between the tangency points T1 and T2, on the curve, is T1T2 = 174.568 m. Using the theodolite and tape at 15 m intervals of through chaining, find the deflection angle for the first sub-chord. Select one a. Deflection angle for short chord is 0 47 88" b. Deflection angle for short chord is 0 49 38.8 c Defleetion angle for short chord is 0 d. Deflection angle for shortchord is 0 50 88
Transcribed Image Text:V 36- A horizontal curve T1T2. having a radius R = 530 m, is to join two straights intersecting at point I with an angle A and a forward chaining 2532.325 m. The distance between the tangency points T1 and T2, on the curve, is T1T2 = 174.568 m. Using the theodolite and tape at 15 m intervals of through chaining, find the deflection angle for the first sub-chord. Select one a. Deflection angle for short chord is 0 47 88" b. Deflection angle for short chord is 0 49 38.8 c Defleetion angle for short chord is 0 d. Deflection angle for shortchord is 0 50 88
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