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V, = {2i} m/s V, = {0.448v½i + 0.894v,j} m/s = {5 cos 0 i + 5 sin 0 j} m/s %3D 目。 Vb/r v, = 2 m/s 5 m/s Vh = Vr + Vb/r 50 m {0.448v,i + 0.894vpj} = {2i} + {5 cos 0 i + 5 sin 0 j} 0.448v, = 2 + 5 cos 0 0.894v, = 5 sin 0 %3D -25 m 50 P = tan-1 25 v = 5.57 m/s 0 = 84.3° P = 63.4°

V, = {2i} m/s V, = {0.448v½i + 0.894v,j} m/s = {5 cos 0 i + 5 sin 0 j} m/s %3D 目。 Vb/r v, = 2 m/s 5 m/s Vh = Vr + Vb/r 50 m {0.448v,i + 0.894vpj} = {2i} + {5 cos 0 i + 5 sin 0 j} 0.448v, = 2 + 5 cos 0 0.894v, = 5 sin 0 %3D -25 m 50 P = tan-1 25 v = 5.57 m/s 0 = 84.3° P = 63.4°

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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how do i solve theta and Vb from the two equations circled in blue?

V, = {2i} m/s Vô = {0.448vµi + 0.894výj} m/s Vp/r = {5 cos 0 i + 5 sin 0 j} m/s v, = 2 m/s %3D 5 m/s 50 m Vh = Vr + Vb/r {0.448v,i + 0.894vpj} = {2i} + {5 cos 0 i + 5 sin 0 j} 0.448vp = 2 + 5 cos 0 0.894vb = 5 sin 0 -25 m 50 P = tan-1 25/ vp = 5.57 m/s P = 63.4° 0 = 84.3º
Transcribed Image Text:V, = {2i} m/s Vô = {0.448vµi + 0.894výj} m/s Vp/r = {5 cos 0 i + 5 sin 0 j} m/s v, = 2 m/s %3D 5 m/s 50 m Vh = Vr + Vb/r {0.448v,i + 0.894vpj} = {2i} + {5 cos 0 i + 5 sin 0 j} 0.448vp = 2 + 5 cos 0 0.894vb = 5 sin 0 -25 m 50 P = tan-1 25/ vp = 5.57 m/s P = 63.4° 0 = 84.3º
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