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u/within 159 Part 3 of 4 Step 3: Find the p-value of the test statistic. 1 = *2 = 4 = I5 = ANOVA Table SS df MS F Between Within P(F2v▼

u/within 159 Part 3 of 4 Step 3: Find the p-value of the test statistic. 1 = *2 = 4 = I5 = ANOVA Table SS df MS F Between Within P(F2v▼

MATLAB: An Introduction with Applications
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
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J between ehomihatór degrees of freedom dfwithin 159 Part 3 of 4 Step 3: Find the p-value of the test statistic. I3 = ANOVA Table SS df MS F Between Within P(F2v
Transcribed Image Text:J between ehomihatór degrees of freedom dfwithin 159 Part 3 of 4 Step 3: Find the p-value of the test statistic. I3 = ANOVA Table SS df MS F Between Within P(F2v
i myopenmat 240159#/skip/1 Enrique teaches five sections of Introductory Psychology. He wants to know whether or not the average score on the second exam is the same for all five sections. Enrique's student's exam scores are listed below. Use an ANOVA test with a level of significance of 6% to test whether the average score is the same for all five sections. Section 1: 80, 80, 84, 88, 85, 89, 80, 79, 85, 80, 70, 82, 76, 86, 72, 84, 80, 79, 87, 74, 81, 86, 74, 79, 81, 77, 75, 76, 82, 76, 84, 80, 88, 92 Section 2: 78, 90, 77, 83, 79, 82, 82, 89, 78, 82, 81, 81, 80, 85, 81, 84, 86, 84, 75, 81, 82, 80, 83, 83, 81, 86, 85, 82, 79, 81, 82 Section 3: 82, 80, 78, 81, 82, 83, 83, 81, 76, 81, 84, 78, 75, 86, 83, 89, 79, 84, 80, 80, 77, 76, 80, 81, 79, 76, 79, 87, 77, 85, 82, 85, 81, 85, 75, 83, 87, 84, 79 Section 4: 84, 88, 77, 87, 89, 83, 88, 83, 84, 70, 85, 82, 82, 84, 83, 82, 78, 83, 82, 85, 78, 81, 78, 86, 87 Section 5: 83, 85, 78, 82, 82, 87, 82, 90, 80, 84, 87, 83, 89, 81, 80, 89, 82, 83, 84, 92, 85, 79, 83, 91, 84, 84, 81, 82, 84, 89, 88, 73, 86, 78, 77 Step 1: State the null and alternative hypotheses. Ho: P1 = P2 = P3 = P4 = Ps Ha: At least one mean isn't equal to the other means v Part 2 of 4 Step 2: Assuming the null hypothesis is true, determine the features of the distribution of test statistics. We will use a(n) F vv distribution with numerator degrees of freedom 159 d fpetween and denominator degrees of freedom d fwithin = 4 Part 3 of 4
Transcribed Image Text:i myopenmat 240159#/skip/1 Enrique teaches five sections of Introductory Psychology. He wants to know whether or not the average score on the second exam is the same for all five sections. Enrique's student's exam scores are listed below. Use an ANOVA test with a level of significance of 6% to test whether the average score is the same for all five sections. Section 1: 80, 80, 84, 88, 85, 89, 80, 79, 85, 80, 70, 82, 76, 86, 72, 84, 80, 79, 87, 74, 81, 86, 74, 79, 81, 77, 75, 76, 82, 76, 84, 80, 88, 92 Section 2: 78, 90, 77, 83, 79, 82, 82, 89, 78, 82, 81, 81, 80, 85, 81, 84, 86, 84, 75, 81, 82, 80, 83, 83, 81, 86, 85, 82, 79, 81, 82 Section 3: 82, 80, 78, 81, 82, 83, 83, 81, 76, 81, 84, 78, 75, 86, 83, 89, 79, 84, 80, 80, 77, 76, 80, 81, 79, 76, 79, 87, 77, 85, 82, 85, 81, 85, 75, 83, 87, 84, 79 Section 4: 84, 88, 77, 87, 89, 83, 88, 83, 84, 70, 85, 82, 82, 84, 83, 82, 78, 83, 82, 85, 78, 81, 78, 86, 87 Section 5: 83, 85, 78, 82, 82, 87, 82, 90, 80, 84, 87, 83, 89, 81, 80, 89, 82, 83, 84, 92, 85, 79, 83, 91, 84, 84, 81, 82, 84, 89, 88, 73, 86, 78, 77 Step 1: State the null and alternative hypotheses. Ho: P1 = P2 = P3 = P4 = Ps Ha: At least one mean isn't equal to the other means v Part 2 of 4 Step 2: Assuming the null hypothesis is true, determine the features of the distribution of test statistics. We will use a(n) F vv distribution with numerator degrees of freedom 159 d fpetween and denominator degrees of freedom d fwithin = 4 Part 3 of 4
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