ut + yux - xuy=0, u(0, x, y) = e(x-1)² – (y−1)²

Q: Find y as a function of a if y(0)2, y'(0) = 3, "(0) = -13. y(x) = y″ − 4y″ − y′ + 4y = 0,

A: Given a differential equation:initial conditions are:

Q: Find F′(x).

A: Given Data The integral function is F(x)=ꭍxx+2(4t+1)dt.   Solve the given integral function,

Q: ' (x² +2)+4x(y² +2y+1)=0, y(0) =1.

A:

Q: Find y as a function of t if y(4) = 6, y (4) = 4. y = 121y" - 132y +36y = 0,

A:

Q: Find y as a function of x if x'y" + 5xy' + 4y = 0, y(1) = 9, y'(1) = -2. y =

A: Solution :-

Q: Solve the ODE  y'+(1/x)y-ex=0, when x>0

A:

Q: let h(y)=(y-3y2)5(y2+2)6  h'(y) in simplified form.

A:

Q: x(3-5x) 2. dx (3x- 1)(x – 1)²

A:

Q: Find y as a function of a if y(1) = -4, y'(1) = -9. y x²y" + 2xy' - 6y = 0,

A:

Q: Find y as a function of a if y(0) = 6, y'(0) = 24, y"(0) = 108. y" + 36y' = 0,

A: y′′′+36y′=0y(0)=6,y′(0)=24,y′′(0)=108.The characteristic equation…

Q: Find y as a function of t if y(0) = 2, y'(0) = 5. y(t) = 100y" +9y = 0,

A:

Q: Answer: y = -(e-x + c)/(1 + x2)

A: Given differential equation is,

Q: Find y as a function of if y(0) = 19, y'(0) = 19, y"(0) = 4, y"(0) = 0. y(x) = y(4) 4y" + 4y = 0,

A: y(4)−4y′′′+4y′′=0y(0)=19,y′(0)=19,y′′(0)=4,y′′′(0)=0

Q: (2t – 3)·e -t²+3t dt 3 2/Inx dx . X (2у-3)12

A:

Q: Find y': Vä+1 VI+1 .2 %3D

A: Answer and explanation is given below