Using your molarity for the vinegar solution, how many grams of sodium bicarbonate would be required to completely react with all of the acetic acid in the 100 mL of vinegar? MM NaHCO3 is 84.007 g/mol. a. 0.67 grams b. 6.7 grams C. 67 grams d. 672 grams

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Molarity of vinegar solution is .8 M

**Question:**

Using your molarity for the vinegar solution, how many **grams of sodium bicarbonate** would be required to completely react with all of the acetic acid in the 100 mL of vinegar? MM NaHCO₃ is 84.007 g/mol.

**Options:**

- a. 0.67 grams
- b. 6.7 grams
- c. 67 grams
- d. 672 grams
Transcribed Image Text:**Question:** Using your molarity for the vinegar solution, how many **grams of sodium bicarbonate** would be required to completely react with all of the acetic acid in the 100 mL of vinegar? MM NaHCO₃ is 84.007 g/mol. **Options:** - a. 0.67 grams - b. 6.7 grams - c. 67 grams - d. 672 grams
**Chemical Reaction:**

**Equation:**  
\[ \text{CH}_3\text{COOH}_{(aq)} + \text{NaHCO}_3_{(s)} \rightarrow \text{NaCH}_3\text{COO}_{(aq)} + \text{H}_2\text{O}_{(l)} + \text{CO}_2_{(g)} \]

**Description:**  
This chemical equation represents the reaction between acetic acid (\[\text{CH}_3\text{COOH}_{(aq)}\]) and sodium bicarbonate (\[\text{NaHCO}_3_{(s)}\]) which results in the formation of sodium acetate (\[\text{NaCH}_3\text{COO}_{(aq)}\]), water (\[\text{H}_2\text{O}_{(l)}\]), and carbon dioxide (\[\text{CO}_2_{(g)}\]).

**States of Matter:**
- \((aq)\) indicates that the substance is in an aqueous solution.
- \((s)\) denotes that the substance is in a solid state.
- \((l)\) signifies that the substance is in a liquid state.
- \((g)\) shows that the substance is in a gaseous state.

**Explanation:**  
This reaction is a classic example of an acid-base reaction, where acetic acid (a weak acid) reacts with sodium bicarbonate (a basic salt). The carbon dioxide gas produced is what leads to the fizzing effect commonly observed during this reaction. This reaction is often demonstrated in educational settings to show gas evolution and acid-base reactions.
Transcribed Image Text:**Chemical Reaction:** **Equation:** \[ \text{CH}_3\text{COOH}_{(aq)} + \text{NaHCO}_3_{(s)} \rightarrow \text{NaCH}_3\text{COO}_{(aq)} + \text{H}_2\text{O}_{(l)} + \text{CO}_2_{(g)} \] **Description:** This chemical equation represents the reaction between acetic acid (\[\text{CH}_3\text{COOH}_{(aq)}\]) and sodium bicarbonate (\[\text{NaHCO}_3_{(s)}\]) which results in the formation of sodium acetate (\[\text{NaCH}_3\text{COO}_{(aq)}\]), water (\[\text{H}_2\text{O}_{(l)}\]), and carbon dioxide (\[\text{CO}_2_{(g)}\]). **States of Matter:** - \((aq)\) indicates that the substance is in an aqueous solution. - \((s)\) denotes that the substance is in a solid state. - \((l)\) signifies that the substance is in a liquid state. - \((g)\) shows that the substance is in a gaseous state. **Explanation:** This reaction is a classic example of an acid-base reaction, where acetic acid (a weak acid) reacts with sodium bicarbonate (a basic salt). The carbon dioxide gas produced is what leads to the fizzing effect commonly observed during this reaction. This reaction is often demonstrated in educational settings to show gas evolution and acid-base reactions.
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