Using V = 3 mV, and given the voltage across an inductor L = 15 mH as shown in Fig. P6.25, determine the equation of current as a function of time across the inductor during the time Oms <= t <= 1 ms. Assuming the solution looks like i(t) = Xt² + C, what is the value of X? For your answer, just put the value of X in Amperes/s² (there should only be a number in your answer). v(t) (MV) A V Figure P6.25 1 2 (ms) W
Using V = 3 mV, and given the voltage across an inductor L = 15 mH as shown in Fig. P6.25, determine the equation of current as a function of time across the inductor during the time Oms <= t <= 1 ms. Assuming the solution looks like i(t) = Xt² + C, what is the value of X? For your answer, just put the value of X in Amperes/s² (there should only be a number in your answer). v(t) (MV) A V Figure P6.25 1 2 (ms) W
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
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**Problem Statement:**
Using \( V = 3 \, \text{mV} \), and given the voltage across an inductor \( L = 15 \, \text{mH} \) as shown in Fig. P6.25, determine the equation of current as a function of time across the inductor during the time \( 0 \, \text{ms} \leq t \leq 1 \, \text{ms} \).
Assuming the solution looks like \( i_L(t) = Xt^2 + C \), what is the value of \( X \)?
*For your answer, just put the value of \( X \) in Amperes/\( s^2 \) (there should only be a number in your answer).*
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**Figure P6.25 Explanation:**
- The graph shows a voltage \( v(t) \) over time.
- The y-axis represents voltage in millivolts (mV), with a reference point noted as \( V \).
- The x-axis represents time in milliseconds (ms).
- The graph has a triangular shape:
- It starts at the origin (0,0).
- Increases linearly to a peak at 1 ms.
- Decreases linearly back to zero at 2 ms.
This triangular waveform provides a visual representation required for calculating the current across the inductor within the specified time frame.
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