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Using two intervals of Simpson's 1/3 rule, an estimate value of ff(x) dx is 11.51. The estimate of the same integral using 4 intervals of Simpson's 1/3 rule is nearly? (a) ¹+(2ƒ (3) − ƒ(5) + 2ƒ (7)) 2 11.51 4 (b) 2 •+₹ (2ƒ(3) − ƒ (5) + 2ƒ (7)) 11.51 2 (c) 2 +3 (2ƒ(3) + ƒ(5) + 2ƒ (7)) 11.51 4 (d) ·+7 (2ƒ(3) + ƒ(5) + 2ƒ (7)) 2

Using two intervals of Simpson's 1/3 rule, an estimate value of ff(x) dx is 11.51. The estimate of the same integral using 4 intervals of Simpson's 1/3 rule is nearly? (a) ¹+(2ƒ (3) − ƒ(5) + 2ƒ (7)) 2 11.51 4 (b) 2 •+₹ (2ƒ(3) − ƒ (5) + 2ƒ (7)) 11.51 2 (c) 2 +3 (2ƒ(3) + ƒ(5) + 2ƒ (7)) 11.51 4 (d) ·+7 (2ƒ(3) + ƒ(5) + 2ƒ (7)) 2

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Using two intervals of Simpson's 1/3 rule, an estimate value of ff(x) dx is 11.51. The estimate of the same integral using 4 intervals of Simpson's 1/3 rule is nearly? 11.51 (a)^2;+ỷ(2f (3) – f(5)+2f(7) 11.51 4 (b) +(2ƒ(3) − ƒ(5) + 2f (7)) 2 11.51 2 (c) +7 (2ƒ(3) + ƒ(5) + 2ƒ(7)) 2 11.51 4 (d) ・+3 (2ƒ(3) + ƒ(5) + 2ƒ(7)) 2
Transcribed Image Text:Using two intervals of Simpson's 1/3 rule, an estimate value of ff(x) dx is 11.51. The estimate of the same integral using 4 intervals of Simpson's 1/3 rule is nearly? 11.51 (a)^2;+ỷ(2f (3) – f(5)+2f(7) 11.51 4 (b) +(2ƒ(3) − ƒ(5) + 2f (7)) 2 11.51 2 (c) +7 (2ƒ(3) + ƒ(5) + 2ƒ(7)) 2 11.51 4 (d) ・+3 (2ƒ(3) + ƒ(5) + 2ƒ(7)) 2
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