Using trigonometric substitutions, S Vx2-9 dx ,x > 3, is equal to: 3x Vx2 _3 – V3sec-) +C Vx2 – 9 – sec -1 + C | - - O This option O This option x² -9 – 3sec(-) + C Vx? - 3 - sec () +€ | KD This option O This option

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