Using the virtual work method, Determine the following: A.) Determine the horizontal and vertical deflections of point G for the truss shown. A = 4500 mm2, E=200 GPa for all members. B.) Determine the vertical deflection of point G of the truss due to the given loads and fabrication errors of an increase of 0.2 mm in length for tension members and 0.25 mm decrease in length for compression members. All Other data remain unchanged. C.) Compute the total vertical deflection at point G. Consider temperature increase of 200C. , All Other data remain unchanged. 50 kN 50 kN B D 4m G 50 kN 50 kN 20 kN 4 at 3 m each = 12 m

Using the virtual work method, Determine the following: A.) Determine the horizontal and vertical deflections of point G for the truss shown. A = 4500 mm2, E=200 GPa for all members. B.) Determine the vertical deflection of point G of the truss due to the given loads and fabrication errors of an increase of 0.2 mm in length for tension members and 0.25 mm decrease in length for compression members. All Other data remain unchanged. C.) Compute the total vertical deflection at point G. Consider temperature increase of 200C. , All Other data remain unchanged. 50 kN 50 kN B D 4m G 50 kN 50 kN 20 kN 4 at 3 m each = 12 m

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Question

Using the virtual work method, Determine the following:
A.) Determine the horizontal and vertical deflections of point G for the truss shown. A =
4500 mm2, E=200 GPa for all members.
B.) Determine the vertical deflection of point G of the truss due to the given loads and
fabrication errors of an increase of 0.2 mm in length for tension members and 0.25 mm
decrease in length for compression members. All Other data remain unchanged.
C.) Compute the total vertical deflection at point G. Consider temperature increase of 200C.
All Other data remain unchanged.
50 kN
50 kN
B
C D
4m
H
G
50 kN
50 kN
20 kN
4 at 3 m each = 12 m

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