Using the Value of a Function InExercises 37–42, use the given value toevaluate each function.37. sin t = 12 38. sin(−t) = 38(a) sin(−t) (a) sin t(b) csc(−t) (b) csc t39. cos(−t) = −15 40. cos t = −34(a) cos t (a) cos(−t)(b) sec(−t) (b) sec(−t)41. sin t = 45 42. cos t = 45(a) sin(π − t) (a) cos(π − t)(b) sin(t + π) (b) cos(t + π)
Using the Value of a Function InExercises 37–42, use the given value toevaluate each function.37. sin t = 12 38. sin(−t) = 38(a) sin(−t) (a) sin t(b) csc(−t) (b) csc t39. cos(−t) = −15 40. cos t = −34(a) cos t (a) cos(−t)(b) sec(−t) (b) sec(−t)41. sin t = 45 42. cos t = 45(a) sin(π − t) (a) cos(π − t)(b) sin(t + π) (b) cos(t + π)
Algebra and Trigonometry (MindTap Course List)
4th Edition
ISBN:9781305071742
Author:James Stewart, Lothar Redlin, Saleem Watson
Publisher:James Stewart, Lothar Redlin, Saleem Watson
Chapter5: Trigonometric Functions: Right Triangle Approach
Section5.4: Inverse Trigonometric Functions And Right Triangles
Problem 1E: For a function to have an inverse, it must be ___________. To define the inverse sine function, we...
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Using the Value of a
Exercises 37–42, use the given value to
evaluate each function.
37. sin t = 1
2 38. sin(−t) = 3
8
(a) sin(−t) (a) sin t
(b) csc(−t) (b) csc t
39. cos(−t) = −1
5 40. cos t = −3
4
(a) cos t (a) cos(−t)
(b) sec(−t) (b) sec(−t)
41. sin t = 4
5 42. cos t = 4
5
(a) sin(π − t) (a) cos(π − t)
(b) sin(t + π) (b) cos(t + π)
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