Using the trigonometric substitution technique, the integral tan¹0d0 sece S f sin sin 40d0 cose tan¹0d0 sec²0 S tan¹0d0 sec ³0 S₁ x Adx (1+x²) 3/2 is equivalent to

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A: If you have any questions let me know in comment box thankyou for your question.

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A:

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A:

Q: 1. Evaluate 4 (sec²x tan²x ). dx

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A:

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A:

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A:

Q: sin 20x sin 21x dx =

A:

Q: Find S(-sin³0 – sin@cos20)d0

A: This can be solved as follows: