Using the table attached answer part A and B. Let us use the following notation for events: A = aggressive approach, Pa = passive approach, S = sale, N = no sale. So, P(A) is the probability that an aggressive approach was used, and so on. A) P(N | A) = B) P(A or S) =

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Using the table attached answer part A and B. Let us use the following notation for events: A = aggressive approach, Pa = passive approach, S = sale, N = no sale. So, P(A) is the probability that an aggressive approach was used, and so on.

A) P(N | A) =

B) P(A or S) =

Sale
No Sale
Row Total
Aggressive
Passive
270
310
580
490
90
580
Column Total
760
400
1160
Transcribed Image Text:Sale No Sale Row Total Aggressive Passive 270 310 580 490 90 580 Column Total 760 400 1160
Expert Solution
Step 1

A).

PN = Probability that there is n " no sale" of automobile

= Number of "no sales"Total number of customers participated in the seminar

= 4001160

= 0.3448

PN | A =Number of agressive approaches used in "no sale" of automobileTotal number of agressive approach used 

               = 310580

              = 0.5344

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