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Using the superposition principle, find ix in the circuit given below, where R= 7 Q. Please report your answer so the magnitude is positive and all angles are in the range of negative 180 degrees to positive 180 degrees. 10cos(2t + 10°) A ell -100 F 4 H www ix 20cos(2t - 60°) V The component of the current due to the voltage source it is 9.9228 The component of the current due to the current source is 2 2.4807 The value of ix= 12.28 cos(2t+ (-105.78 )) A. cos(2t+ (-109.745 >)) A. cos(2t+ (-89.7449 °)) A.

Using the superposition principle, find ix in the circuit given below, where R= 7 Q. Please report your answer so the magnitude is positive and all angles are in the range of negative 180 degrees to positive 180 degrees. 10cos(2t + 10°) A ell -100 F 4 H www ix 20cos(2t - 60°) V The component of the current due to the voltage source it is 9.9228 The component of the current due to the current source is 2 2.4807 The value of ix= 12.28 cos(2t+ (-105.78 )) A. cos(2t+ (-109.745 >)) A. cos(2t+ (-89.7449 °)) A.

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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Using the superposition principle, find ix in the circuit given below, where R= 7 Q. Please report your answer so the magnitude is positive and all angles are in the range of negative 180 degrees to positive 180 degrees. 10cos(2t + 10°) A ell -100 F 4 H www ix 20cos(2t - 60°) V The component of the current due to the voltage source it is 9.9228 The component of the current due to the current source is 2 2.4807 The value of ix= 12.28 cos(2t+ (-105.78 °)) A. cos(2t+ (-109.745 >)) A. cos(2t+ (-89.7449 °)) A.
Transcribed Image Text:Using the superposition principle, find ix in the circuit given below, where R= 7 Q. Please report your answer so the magnitude is positive and all angles are in the range of negative 180 degrees to positive 180 degrees. 10cos(2t + 10°) A ell -100 F 4 H www ix 20cos(2t - 60°) V The component of the current due to the voltage source it is 9.9228 The component of the current due to the current source is 2 2.4807 The value of ix= 12.28 cos(2t+ (-105.78 °)) A. cos(2t+ (-109.745 >)) A. cos(2t+ (-89.7449 °)) A.
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